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MaRussiya [10]
4 years ago
6

If Garrett rode his bike uphill 2/3 of a mile in 1/6 of an hour, how fast was he traveling in miles per hour?

Mathematics
2 answers:
My name is Ann [436]4 years ago
7 0

Distance traveled by Garrett = \frac{2}{3} mile

Time taken to travel the distance = \frac{1}{6} hour

We have to find how fast was he traveling in miles per hour, means we have to calculate the speed.

Speed is a measure of how quickly an object moves from one place to another. It is equal to the distance traveled divided by the time.

Speed = Distance traveled \div Time taken

= \frac{2}{3} \div \frac{1}{6}

= \frac{2}{3} \times {6}

= 4 miles per hour

Therefore, Garrett traveled at the speed of 4 miles per hour.

11111nata11111 [884]4 years ago
6 0
You have to multiply by six to see how fast he is riding in mph. He is going 4 mph.
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What is the degree of the polynomial?
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Answer:

2

Step-by-step explanation:

The degree of the polynomial is the highest exponent of an expression. When more than one variable is present, its is the sum of exponents on one term in the expression.

The polynomial has terms xy, 3x^2, -7 and x. The term with the highest exponent sum is xy or 3x^2. Both have degree 2. The degree of the polynomial is 2.

8 0
3 years ago
A) Rate (R)<br>24/5<br>Time = 1 month<br>Interest = Rs. 39.96​
yKpoI14uk [10]

Answer:  P = $ 1,998.01

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 24%/100 = 0.24 per year,

putting time into years for simplicity,

1 months ÷ 12 months/year = 0.083333 years,

then, solving our equation

P = 39.96 / ( 0.24 × 0.083333 ) = 1998.007992032

P = $ 1,998.01

The principal required to

accumulate interest of $ 39.96

on a rate of 24% per year for 0.083333 years (1 months) is $ 1,998.01.

5 0
3 years ago
Help and show all work please
Aloiza [94]

Answer:

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
1.) What is the value of cosθ given that (−5, −4) is a point on the terminal side of θ?
jeka57 [31]

Answer:

1) C

2) D

Step-by-step explanation:

1)

We want to find the value of cos(θ) given that (-5, -4) is a point on the terminal side of θ.

This is represented by the diagram below.

Recall that cosine is the ratio of the adjacent side to the hypotenuse.

Find the hypotenuse:

\displaystlye \begin{aligned} a^2 + b^2 &= c^2 \\ c &= \sqrt{a^2 + b^2} \\ &= \sqrt{(4)^2 + (5)^2} \\ &= \sqrt{41}\end{aligned}

The adjacent side with respect to θ is -5 and the hypotenuse is √41. Hence:

\displaystyle \begin{aligned}\cos \theta &= \frac{(-5)}{(\sqrt{41})} \\ \\ &= - \frac{5\sqrt{41}}{41}  \end{aligned}

Our answer is C.

2)

We want to find the value of sin(θ) given that (-6, -8) is a point on the terminal side of θ.

This is represented in the diagram below.

Likewise, find the hypotenuse:

\displaystyle c = \sqrt{(-6)^2 + (-8)^2} = 10

Sine is given by the ratio of the opposite side to the hypotenuse.

The opposite side with respect to θ is -8 and the hypotenuse is 10. Hence:

\displaystyle \begin{aligned}\sin \theta &= \frac{(-8)}{(10)} \\ \\ &= -\frac{4}{5} \end{aligned}

Our answer is D.

8 0
3 years ago
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