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natta225 [31]
3 years ago
7

Break the dividend into smaller parts that are easier to divide write the equivalent name you used.

Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0
96 divided bye two is 48 i believe then 48 then 24 then 12 then 6 hoped i helped 
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PLEASE HELP been stuck on this for a while
marysya [2.9K]

Answer:

I believe it's D but I'm not 100 percent sure. I hope this helped I'm sorry I couldn't help more <3

4 0
3 years ago
Write the phrase as an expression. Five more that six divided by a number r.
Nuetrik [128]

Answer:

6/r + 5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Simplify -8 + 17n + 10 + 8n
Vinil7 [7]

-8 + 17n + 10 + 8n =


25n + 2

6 0
3 years ago
Which expression has a negative value?
7nadin3 [17]

Answer: The answer would be B

Step-by-step explanation:

I had a test like this so I kinda know wut the answer is a few weeks or so ago but u need to multiply -5 • 5 (which would be negative since it has one negative sign) then multiply -5 • -5 (since it has another negative it’s positive) then u just multiply the answers that u got from the times 5 u did -bonus if it’s 1 negatives it’s a negative but if it’s 2 negatives it’s a positive

4 0
3 years ago
Solve the following equation:
Rama09 [41]

Complete the square.

z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0

\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4

Use de Moivre's theorem to compute the square roots of the right side.

w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)

\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2

Now, taking square roots on both sides, we have

z^2 + \dfrac12 = \pm w^{1/2}

z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2

Use de Moivre's theorem again to take square roots on both sides.

w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)

\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}

w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)

\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}

3 0
2 years ago
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