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Butoxors [25]
3 years ago
8

Solve it pleasePLEASE*​

Mathematics
1 answer:
shutvik [7]3 years ago
5 0

Answer:

(L-3)(L) or L^2-3L

Step-by-step explanation:

The area of any rectangle is w*l, where w is the width and l is the length. Plugging in our width and length, we have that the area of the rectangle is (L-3)(L) or L^2-3L

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Marrrta [24]

Answer:

4

Step-by-step explanation:

4

4 0
4 years ago
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Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha
vodomira [7]

we have

\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x

Combine like terms in both sides

(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x

we know that

(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x

substitute in the expression above

\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x-----> equation A        

Multiply equation A by 5*3*2=30 both sides

30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)

48x+20=15-6x ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

48x+6x=15-20

54x=-5 ---------> equation C

Solve for x

x=-\frac{5}{54} =-0.09

We are going to proceed to verify each case to determine the solution.

<u>Case a)</u> \frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x

the case a) is equal to the equation A

so

the case a) have the same solution that the given equation

<u>Case b)</u> 18x+20+30x=15-6x

Combine like terms in left side

(18x+30x)+20=15-6x

(48x)+20=15-6x

the case b) is equal to the equation B

so

the case b) have the same solution that the given equation

<u>Case c)</u> 18x+20+x=15-6x

Combine like terms in left side

(18x+x)+20=15-6x

(19x)+20=15-6x

19x+6x=15-20\\25x=-5\\x=-0.20

-0.20\neq -0.09

therefore

the case c) not have the same solution that the given equation

<u>Case d)</u> 24x+30x=-5

Combine like terms in left side

54x=-5

the case d) is equal to the equation C

so

the case d) have the same solution that the given equation

<u>Case e)</u> 12x+30x=-5

Combine like terms in left side

42x=-5

x=-5/42=-0.12

-0.12\neq -0.09

therefore

the case e) not have the same solution that the given equation

therefore

<u>the answer is</u>

case a) \frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x

case b) 18x+20+30x=15-6x

case d) 24x+30x=-5

7 0
4 years ago
Read 2 more answers
Find AA and BB that make the equation true. Verify your results.
CaHeK987 [17]

Answer:

a. A = -1 and B = 1

b. A = 7 and B = -5

Step-by-step explanation:

a.

\frac{A}{x+1} +\frac{B}{x-1}  = \frac{2}{x^2-1}

\frac{A*(x-1)+B*(x+1)}{(x+1)*(x-1)} = \frac{2}{x^2-1}

\frac{Ax - A + Bx + B}{x^2 -1} = \frac{2}{x^2-1}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 0

(A + B)x = 0

A + B = 0

A = -B

B - A = 2

B - (-B) = 2

2B = 2

B = 1  and A = -1

b.

\frac{A}{x+3} + \frac{B}{x +2} = \frac{2x -1}{x^2+5x+6}

\frac{A*(x+2) + B*(x+3)}{(x+3)*(x+2)} = \frac{2x-1}{x^2+5x+6}

\frac{Ax + 2A + Bx + 3B}{x^2 + 5x + 6} = \frac{2x-1}{x^2+5x+6}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 2x

(A + B)x = 2x

A + B = 2

A = 2 - B

2A + 3B = -1

2*(2-B) + 3B = -1

4 - 2B + 3B = -1

B = -5  and A = 2 - (-5) = 7

5 0
4 years ago
Please help :)<br> NO LINKS<br> NO silly answers just for fun<br> Please answer Thanks!
Mashcka [7]

Answer:

The second one

Step-by-step explanation:

The equation for volume is l*w*h

l=length

w=width

h=hight

All you have to do is find the answer multiplying all of the numbers together.

Hope this helps!

8 0
3 years ago
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Consider the three roads, where the length of Road 1 is 320 feet. What is the approximate length of Road 3? A. 118.7 feet B. 232
Scorpion4ik [409]

Answer:

D

Step-by-step explanation:

Use law of sines

320ft/sin(17) = x ft/sin(128)

x = 862.5

Find 17 degrees using 180 - 128 - 35 = 17

5 0
4 years ago
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