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tangare [24]
3 years ago
15

I NEED HELP ASAP SOMEONE HELP ME PLEASE, I MEDD SOMEONE WHO CAN HELP ME WITH THE REST OF MY QUESTIONS

Mathematics
2 answers:
Vikentia [17]3 years ago
8 0

Answer:

Step-by-step explanation:

K(0 , 4)

Midpoint M (3 , 3)

Let Point  L(x₂ , y₂)

Midpoint= (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}\\\\\\ (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2}) = (3 , 3)\\\\\\ (\frac{0+x_{2}}{2},\frac{4+y_{2}}{2}) = ( 3 , 3)\\\\\\

Compare x and y coordinates

\frac{x_{2}}{2}=3    ;  \frac{4+y_{2}}{2} = 3

Cross multiply,

x₂ = 3*2     ; 4 + y₂ = 3*2

x₂ = 6        ;  4+ y₂ = 6

                         y₂ = 6- 4

                          y₂ = 2

L(6 , 2)

eduard3 years ago
6 0

Answer:

6,2

Step-by-step explanation:

I don't think you want to know how I did it, it's pretty boring for most people except me

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See below ~

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<u>Question #8</u>

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<u></u>

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Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.
saw5 [17]

Car 1: It is an exponential function that is given as P = 18,500 (0.9595)ⁿ and the price after 10 years is $12,235.5.

Car 2: It is a linear function that is given as 2000x + 3y = 55500 and the price after 10 years is $11,833.33.

And Yes, there is a significant difference.

<h3>What is a function?</h3>

A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.

Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.

Car 1 (value in dollars)

Year 1: 18,500

Year 2: 17,390

Year 3: 16,346.60

Car 2 (value in dollars)

Year 1: 18,500

Year 2: 17,500

Year 3: 16,500

The exponential function describes car 1.

Then the function will be

\rm P = 18500\times (0.95995)^n

The linear function describes car 2.

\rm y \ - \ 18500 = \dfrac{-2000}{3}(x - 0)\\\\\\3y - 55500 = -2000x\\\\\\2000x +3y = 55500

Then the value of the car 1 after 10 years will be

\rm P = 18500\times (0.95995)^{10}\\\\\\P = \$ \ 12,235.5

Then the value of the car 2 after 10 years will be

\rm 2000 \times 10 +3y = 55500\\\\y =  \$ \ 11,833.33

Yes, there is a significant difference.

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

5 0
2 years ago
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