<span>(5x^2 + 2x + 11) − (7 + 4x − 2x^2)
= </span>5x^2 + 2x + 11 − 7 - 4x + 2x^2
= 7x^2 - 2x + 4
Answer: 1. x^2-5x+4
2. x^2-7x+6
3. x^3-7x^2+11x-5
4. x-5
Step-by-step explanation:
1. x^2-6x+5+x-1=
x^2-6x+x+5-1=x^2-5x+4
2. x^2-6x+5-(x-1)=
x^2-6x+5-x+1=
x^2-6x-x+5+1=x^2-7x+6
3. (x^2-6x+5) * (x-1)=
x(x^2-6x+5)-1(x^2-6x+5)=
x^3-6x^2+5x-x^2+6x-5=
x^3-6x^2-x^2+5x+6x-5=x^3-7x^2+11x-5
4. (x^2-6x+5)/(x-1)=
(x^2-x-5x+5)/(x-1)=
(x(x-1)-5(x-1))/(x-1)=
(x-5)(x-1)/(x-1)=x-5
The total circle has a measure of 2π radian, so this portion is 1/(2π) of the whole circle
the circumference of the whole circle is 2πr
1/(2π) of 2πr=3.07
r=3.07
Answer:
x = 67
Step-by-step explanation:
∠ CRQ = ∠ BQR = 113° ( Alternate angles )
∠ CRQ and ∠ CRS are adjacent angles and supplementary, that is
x + 113 = 180 ( subtract 113 from both sides )
x = 67
Step-by-step explanation:
Area of Shaded part
= 2 * Area of Quarter-circle - Area of Square
= 0.5π(8)² - 8²
= 32(π - 2)cm².
Perimeter of Shaded part
= 0.5 * 2π(8)
= 8πcm.
