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mezya [45]
3 years ago
5

3.6 In mice, the allele C for colored fur is dominant over the allele c for white fur, and the allele V for normal behavior is d

ominant over the allele v for waltzing behavior, a form of discoordination. Give the genotypes of the parents in each of the following crosses: (a) Colored, normal mice mated with white, normal mice pro- duced 29 colored, normal and 10 colored, waltzing progeny. (b) Colored, normal mice mated with colored, normal mice produced 38 colored, normal, 15 colored, waltzing, 11 white, normal, and 4 white, waltzing progeny. (c) Colored, normal mice mated with white, waltzing mice produced 8 colored, normal, 7 colored, waltzing, 9 white, normal, and 6 white, waltzing progen
Biology
1 answer:
KengaRu [80]3 years ago
3 0

Answer:

a)  Parents Genotype should be (CC,Vv) and (cc,VV).

b) The genotypes of the parents are (Cc,Vv) and (Cc,Vv).

c) The genotypes of the parents are (Cc,Vv) and (cc,vv).

Explanation:

<h2>                                      (<u>a)</u> </h2>

Mating has occured between a normal colored mice whose genotype is C_,V_  and normal white  mice with genotype cc,V_. The offsprings are as follows :

1) normal mice produced 29 colored

2) 10 colored, waltzing progeny.

Thus all offspring are normal. The genotype of the first parent should therefore be CC. Waltzing trait is produced. The V gene should therefore be heterozygous in both traits.

Hence The parent genotypes should be<u> (CC,Vv) and (cc,CV).</u>

<h2>                                      (b)</h2>

In this case the approximate ratio in which the descendants are produced is 9:3:3:1. Hence genotypes of the parents are <u>(Cc,Vv) and (Cc,Vv). </u>

<h2>                                      (<u>c)</u>  </h2>

In this case the approximate ratio in which the offsprings are produced is 1:1:1. The genotypes of the parents are <u>(Cc,Vv) and (cc,vv). </u>

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