Answer:
sry i cant help you bcoz i havent read this type of exercise yet
For the answer to the question above, n the 1st month, the accrued interest is ___ (1/12) * .0525 * 135400
subtract the interest from the payment to find the change in the principal for the 2nd month
find the 2nd month's interest and subtract from the payment to find the amount applied to principal. Then that's it!
In five weeks, there are 35 days. So, the average drop in temperature per day is 40/35 = 8/7 degrees per week. Then in 1 week, 8/7 degrees per day * 7 days per week = 8 degrees per week.Therefore there are 8 degrees drop of temperature in 1 week.
The value of co-efficient of determination is 0.241.
<h3>What is the relationship between linear co-relation co-efficient and co-efficient of determination ?</h3>
The co-efficient of determination R² is similar to the linear correlation co-efficient.
We can think of co-relation of determination as a percentage. It gives us the data for how much percentage of data will fall within the linear co-relation.The higher the percentage the more data falls within.If the coefficient is 0.5 then 50% of data falls within the linear co-relation.
According to the given question
Linear correlation coefficient is -0.491
∴ Co-efficient of determination is (-.491)² which is equal to 0.241.
Learn more about Linear regression here :
brainly.com/question/14313391
#SPJ1
