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Helga [31]
3 years ago
7

Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally

distributed, with a mean of 4.5 millimeters (mm) and a standard deviation of 1.5 mm. For a randomly found shard, find the following probabilities. (Round your answers to four decimal places.)(a) the thickness is less than 3.0 mm(b) the thickness is more than 7.0 mm(c) the thickness is between 3.0 mm and 7.0 mm
Mathematics
1 answer:
storchak [24]3 years ago
8 0

Answer:

a) 0.1587

b) 0.0475

c) 0.7938

Step-by-step explanation:

Let's start defining our random variable.

X : ''Thickness (in mm) of ancient prehistoric Native American pot shards discovered in a Hopi village''

X is modeled as a normal random variable.

X ~ N(μ,σ)

Where μ is the mean and σ is the standard deviation.

To calculate all the probabilities, we are going to normalize the random variable X.

We are going to call to the standard normal distribution ''Z''.

[(X - μ) / σ] ≅ Z

We normalize by subtracting the mean to X and then dividing by standard deviation.

We can find the values of probabilities for Z in a standard normal distribution table.

We are going to call Φ(A) to the normal standard cumulative distribution evaluated in a value ''A''

a)

P(X

P(ZΦ(-1) = 0.1587

b)

P(X>7)=P(\frac{X-4.5}{1.5}>\frac{7-4.5}{1.5})

P(Z>1.666)=1-P(Z\leq 1.666)=

1 - Φ(1.666) = 1 - 0.9525 = 0.0475

c)

P(3

P(-1 Φ(1.666) - Φ(-1) = 0.9525 - 0.1587 = 0.7938

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\huge\text{Hey there!}

\large\text{We cannot  do much of nothing because we don’t have all the information}\\\large\text{to solve.. so we can just simply do process of elimination until we fully find}\\\large\text{the ANSWER you are trying to look for.}

\large\text{Given equation: 25b - 14b}\\\large\text{COMBINE your LIKE TERMS}\\\large\text{\underline{25b - 14b} = 11b}\\\large\text{So, we are looking for an equation that gives us \bf{11b}}

\large\text{Option A.}\downarrow\\\large\text{b(25 - 14)}\\\large\text{DISTRIBUTE: b(25) + b(-14)}\\\bullet\large\text{ Reverts to: 25b - 14b (our ORIGINAL EQUATION) so this can be}\\\large\text{equal to 11b}\\\\\large\text{Option A. could POSSIBLY  be your ANSWER}

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\boxed{\boxed{\large\text{To sum it all up, your ANSWER is: \bf{Option A. b(25 - 14)}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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