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charle [14.2K]
3 years ago
12

How to rewrite 11x+13y=8 in slope intercept form

Mathematics
2 answers:
likoan [24]3 years ago
5 0

Answer

y=-\frac{11}{13}x+\frac{8}{13}

Step-by-step explanation:

Anna [14]3 years ago
3 0

Answer:

y = -(11/13)x + (8/13)  

Step-by-step explanation:

recall slope intercept form of a linear equation takes the general form:

y = mx + b

In this case, simply rearrange the given equation such that it looks like the general equation above.

11x+13y=8  (subtract 11x from both sides)

13y = -11x + 8  (divide both sides by 13)

y = -(11/13)x + (8/13)    (answer)

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Answer:

Step-by-step explanation:

Volume of a prism:

Area of cross section x height

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A college bookstore marks up the price that it pays the publisher for a book by 35%.  If the selling price of a book is $54.00,
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In the diagram below, line AB and line CD intersect at point P. Name the angle that is always congruent to <APC​
Alex Ar [27]

<dpb because they’re vertical angles (they’re directly across from each other)

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3 years ago
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Which equations and/or functions represent the graphed line? Select three options.
Zarrin [17]

Answer:

f(x) = 0.5x + 2

f(x) = 1/2x + 2

y - 3 = 1/2(x - 2)

y - 1 = 0.5(x + 2)

Step-by-step explanation:

In the figure attached, the graphed line is shown.

The missing options are:

<em>f(x) = 0.2x - 4 </em>

<em>f(x) = 0.5x + 2  </em>

<em> f(x) = 1/2x + 2 </em>

<em> y – 3 = 1/2(x – 2) </em>

<em> y – 1 = 0.5(x + 2)</em>

From the picture, we can see that points (0, 2) and (2, 3) are on the line. Then, the slope of the line is:

m = (3 - 2)/(2 - 0) = 1/2 = 0.5

The y-intercept is (0, 2), or b = 2

Therefore, in the slope y-intercept form, the equation is:

f(x) = mx + b

f(x) = 1/2x + 2 = 0.5x + 2

In the point-slope form, the equations is:

y - y1 = m(x - x1)

y - 3 = 1/2(x - 2)

Using point (-2, 1), in the point-slope form, the equation is:

y - y1 = m(x - x1)

y - 1 = 0.5(x + 2)

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3 years ago
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Hi, can someone help me on this. I'm stuck --
CaHeK987 [17]

Answer:

a) Fx=-5N  Fy=-5*sqrt(3) N   b) Fx= 5*sqrt(3) N    Fy=-5N

c) Fx=-5*sqrt(2) N    Fy=-5*sqrt(2)   N

Step-by-step explanation:

The arrow's F ( weight) component on axle x  is Fx= F*sinA  and on axle y is

Fy=F*cosA

a) The x component and y component both are opposite directed to axle x and axle y accordingly.  So both components are negative.

So Fx = - 10*sin(30)= -5 N      Fy= -10*cos(30)= -10*sqrt(3)/2= -5*sqrt (3) N

b) Now the x component  is co directed to axle x , and y component is opposite directed to axle y.

So x component is positive and y components is negative

So Fx = 10*sin(60)= 5*sqrt(3) N       Fy= -10*cos(60)= -10*1/2= -5 N

c)The x component and y component both are opposite directed to axle x and axle y accordingly.  So both components are negative.

So Fx = - 10*sin(45)= -5*sqrt(2)  N    

 Fy= -10*cos(45)= -10*sqrt(2)/2= -5*sqrt (2) N

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3 years ago
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