Hey there
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The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30 and f(x+5)=x^2+kx+30 so
k=13
Now factor x^2+13x+30
Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so
(x+3)(x+10)
So the two zeros occur when x=-3 and -10 the smallest of which is:
x=-10
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Hope this helps you
Answer:
3rd option
Step-by-step explanation:
The range are the values covered on the y- axis
The lowest value is - 2
The highest value is 6
Both points have a solid circle on them indicating y can equal those values
range { y : - 2 ≤ y ≤ 6 }
Answer:
it's B C E
Step-by-step explanation:
D.864,000
<span>to find standard form if the power is positive move the decimal that many places to the right. If the power is negative move the decimal that many times to the left.</span>