Answer:
K ∅ = 1.48 Wb
Explanation:
given data
EA=(82 V/A)
speed = 1,710 rpm
RA = 9Ω
Rad j = 6Ω
RF = 30Ω
voltage VT = 97 V
to find out
Kϕ for the motor in Wb
solution
first we get here shunt field current
shunt field current = ............1
shunt field current =
shunt field current IF = 3.233 A
and
now we get here induced emf for field current that is
induced emf = 82 IF
induced emf = 82 × 3.233
induced emf = 265.133 V
and induced emf EA is also express as
induced emf EA = K∅ω .....................2
EA = K ∅ ×
put here value
265.133 = K ∅ ×
solve we get
K ∅ = 1.48 Wb
Answer and Explanation:
Maintenance Job activity is of great importance for any firm or organization as it is the deciding factor of the firm's smooth functioning of a number of operations in the firm.
This requires the consideration of various factors prior to the maintenance activity which are as follows:
1. Planning:
Proper planning must be done in order to avoid risks and how to effectively control and mitigate risks related to the workplace, personnel, equipment, material, etc and to ensure proper maintenance of the firm and it's resources.
2. Allocation of appropriate tools and equipment:
In order to ensure proper maintenance, appropriate tools and equipment should be allocated to the workers to carry out their tasks properly and to ensure the structural safety and stability.
Some of these includes equipment for protection of personnel, safety ladders, etc.
3. Safe working environment:
Ensuring the safety of the work area by taking proper safety measures like protection against machine faults thus preventing accidents, protection against the unauthorized access and entry in the working area, taking care of power supply and proper power discharges and maintaining clean and hygienic atmosphere for the safe mobility of the material and personnel.
The correct answer to your problem is the answers of a and b
Answer:
23.34 seconds
Explanation:
Flow rate = 1500
Arrival = 800 vehicle per hour
Cycle c = 60 seconds
Dissipation time = 10 seconds
Arrival time = 800/3600 = 0.2222
Rate of departure = 1500/3600 = 0.4167
Traffic density p = 0.2222/0.4167 = 0.5332
Real time = r
r + to + 10 = c
to = c-r-10 ----1
t0 = p*r/1-p ----2
Equate both 1 and 2
C-r-10 = p*r/1-p
60-r-10 = 0.5332r/1-0.5332
50-r = 0.5332r/0.4668
50-r = 1.1422r
50 = 1.1422r + r
50 = 2.1422r
r = 50/2.1422
r = 23.34 seconds