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Whitepunk [10]
3 years ago
10

Can someone please help me

Mathematics
2 answers:
Lesechka [4]3 years ago
7 0
The <u>correct answer</u> is:

Connect two arcs together with a compass.

Explanation:

When inscribing polygons, most polygons require two arcs to be connected at some point.  

For a dodecahedron, we at one point must bisect an angle, which requires connecting two arcs.
For a square, you either bisect angles or draw a perpendicular bisector; both require connecting two arcs.
For an octagon, you bisect quadrants, which requires connecting two arcs.

Doubling the number of sides of an inscribed polygon is done by bisecting the segments of the circle; again, this requires connecting two arcs.
pashok25 [27]3 years ago
4 0
The answer is "Connect two arcs together with a compass".
You can inscribe different regular polygons by creating a circle and connecting two arcs together. There are different procedures and they depends on what kind of regular polygon you will be creating.
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Please answer truefully i giv you brainlistet
jasenka [17]
First: negative 9 and the second is 3 and 9
5 0
3 years ago
To the nearest tenth the value of x that satisfies 2x = −2x + 11 is
Anuta_ua [19.1K]
To solve for variable equations or inequalities, we want to do two things:
1. Reduce one side to variables only
2. Reduce that side to the variable without coefficients.

The given equation is 2x=-2x+11.

Let's perform step 1: reducing one side to variables only. By adding 2x to both sides of the equation, we get 4x=11.

Now let's perform step 2: reducing that side to the variable without coefficients. Since the coefficient of 4x is 4, we need to divide both sides of the equation by 4: x=\frac{11}{4}=2.75. Rounded to the nearest tenth, x=2.8.

So the value of x that satisfies 2x=-2x+11 is x=2.8.
4 0
3 years ago
Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park: A coordinate plane is shown.
Nostrana [21]

Question:

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park.There is a point at (−6, 3) labeled Dog 1. There is a point at (−6, −3) labeled Dog 2.

Which statement best describes the relationship between the positions of the two players?

A.Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

B.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

C.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

D. Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

Answer:

Option B: Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

Explanation:

The position of the Dog 1 is (−6, 3).

The position of the Dog 2 is (−6, -3).

From the graph, we can see that the image of Dog 1 is reflected over x-axis. Because to reflect an image over x-axis, the signs of y-coordinate must be changed.

Hence, Option B is correct.

Thus, Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

7 0
3 years ago
Given that (-5,-6) is on the graph of f(x), find the corresponding point for this function -1/3f(x).
masya89 [10]
<h3>Answer:  (-5, 2)</h3>

Explanation:

We multiply the y coordinate by -1/3 because of the notation (-1/3)*f(x). Recall that y = f(x). The x coordinate stays the same.

5 0
2 years ago
If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?
viktelen [127]

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

4 0
3 years ago
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