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KengaRu [80]
3 years ago
9

Brian compared the absolute values of the numbers−12,34,and−14.Arrange the numbers from least to greatest.

Mathematics
1 answer:
solniwko [45]3 years ago
3 0

Answer:

-12, -14, 34

Step-by-step explanation:

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The perimeter of a rectangle is 128 inches.
Anuta_ua [19.1K]

Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.

<h3>What is the perimeter of a rectangle?</h3>

The perimeter of a rectangle of length l and width w is given as follows:

P = 2(l + w).

The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:

l = x, w = 5(x + 2).

The perimeter is of 128 inches, hence:

128 = 2l + 2w

128 = 2x + 10(x + 2)

128 = 2x + 10x + 20

12x = 108

x = 9.

Hence the length is of 9 inches and the width is of 55 inches.

More can be learned about the perimeter of a rectangle at brainly.com/question/10489198

#SPJ1

6 0
2 years ago
Philip made a total of 9 bracelets and necklaces from 120 inches of cord. He used 8 inches of cord for each bracelet and 20 inch
Viktor [21]

Answer:

So Philip made 5 bracelets and 4 necklaces.

Step-by-step explanation:

Let x = number of bracelets and y = number of necklaces.

Since we have a total of 9 bracelets and necklaces,

x + y = 9 (1)

Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

So, the total length for both is 8x + 20y. Since the total length of cord used is 120 inches,

8x + 20y = 120 (2)

Simplifying it we have

2x + 5y = 30  (3).

Writing equations (1) and (3) in matrix form, we have

\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]

Using Cramer's rule to solve for x and y,

x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

3 0
3 years ago
Solve <br>(3431​)−2/3÷(491​)3/2 <br><br>a. 16807<br>b.343<br>c.49<br>d.2401​
topjm [15]
Try photo math it is very helpful
7 0
3 years ago
HELPPPP PLEASEEEEEEEREEREEEE
Maksim231197 [3]

Answer:

the correct answer is b :)))))!!!

7 0
3 years ago
What is square root of 167?
enot [183]
The square root of 167 would be 12.922847. If you need it rounded to the nearest tenth it would be 12.9

If you need t rounded to the nearest hundredth, it would be 12.92.


Hope this helps :)
7 0
3 years ago
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