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3 years ago

A group of friends wants to go to the amusement park. They have no more than $150

Mathematics

1 answer:

algol [13]3 years ago

7 0

Answer: 17.75p + 8 ≤ 150 OR p ≤ 8

Step-by-step explanation:

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In ΔWXY, the measure of ∠Y=90°, XW = 85, WY = 77, and YX = 36. What is the value of the cosine of ∠W to the nearest hundredth?

tankabanditka [31]

Answer:

0.91

Step-by-step explanation:

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3 years ago

Subtract: (3m2 + 2n) – (m2 + 2n)

maksim [4K]

The negative in front of the second bracket means that it's times by -1 so each of their signs switches:
3m^2+2n-m^2-2n
Add like terms
2m^2
the 2n cancels out

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4 years ago

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A pyramid is placed inside a prism as shown. The pyramid has the same base area, B, as the prism but half the height, h, of the

Alona [7]

The general formula of a pyramid with any base is 1/3 bh where b is the area of the base and h is the height. In this case, the height of the pyramid is said to be twice the height of the prism, h. Hence the area becomes 1/3 b*2h or equal to option A. 2/3 bh

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3 years ago

What is the last operation to be performed when finding the value of this expression?

MArishka [77]

To find out the last operation, we must solve the entire problem.

We are given:

$\frac{5+(-8)}{-3+(-9)(-6)}$

Let's simplify the signs so they don't clutter our equation.

$\frac{5-8}{-3+(-9)(-6)}$

We always need to be sure to use PEMDAS. Since there is no expression to solve in parenthesis and no exponents are present, we will move on to multiplication. We can multiply -9 and -6 in the denominator. When we do that, we get:

$\frac{5-8}{-3+54}$

Next, all you need to do is combine like terms in the numerator and the denominator.

$\frac{-3}{51}$

Simplify.

$-\frac{1}{17}$

To answer the question, the last operation to be performed when finding the value would be division.

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3 years ago

Two ships have a harbor entrance at the same time. The first ship is traveling at a constant 16 mph, while the second is traveli

stepan [7]

So hmm check the picture below

both ships leave at the same time, one is going 16mph, the other 20mph, 2hrs later on the road

at 16mph well, 2hrs is just 16+16, or 32 miles away
20mph for 2hrs, is 20+20, or 40 miles away

using the law of cosines $\bf x = \sqrt{{{ 32}}^2+{{ 40}}^2-2(32)(40)cos(169^o)}$

again, recall, the angle is in degrees, so, when taking the cosine, make sure your calculator is in Degree mode

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3 years ago