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I am Lyosha [343]
3 years ago
15

The variables for Part II of this experiment include the type of material used and the thermal energy transferred by that materi

al. Use the drop-down menus to complete the sentences and identify the independent and dependent variables.
The independent variable, the one that is intentionally manipulated, is the .

The dependent variable, the one that you measure the response in, is the .
Chemistry
2 answers:
AlladinOne [14]3 years ago
5 0

Answer:

The independent variable is the type of material

The dependent variable is the thermal energy transferred by that material

Explanation:

The type of material is independent of the heat flowing through it. While the thermal energy transferred is surely dependent on the material through which it transfers.

lisov135 [29]3 years ago
4 0

Answer:

The first one is the type of energy used

The second one is the thermal energy transferred

Explanation:

I just had the question

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3 years ago
1. How many moles are in 7.32 x 10^24 atoms of iron?
SashulF [63]

Answer:

I believe about 10 moles

Explanation:

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3 years ago
Which is an example of a free expansion of a gas?
katovenus [111]
Free expansion refers to uninhibited or provoked expansion, i.e. it’s expanding on its own, by itself. The only situation in which this occurs is B, as the gas is allowed to expand by itself. A involves a reaction that forces the expansion, C involves the gas performing work, and D involves thermal expansion.

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4 years ago
PLEASE ASAP IT'S TIMED <3​
Sedaia [141]

Answer:

C. NaCl and A. Water(H2O)

Explanation:

Products are on the right side of the equation, reactants are on the left.

5 0
4 years ago
The breakdown of a certain pollutant X in sunlight is known to follow first-order kinetics. An atmospheric scientist studying th
a_sh-v [17]

Explanation:

Change in the concentration of reactant that is consumed in per unit time is known as rate of reaction.

The given chemical reaction will be written as follows.

            X \overset{sunlight}{\rightarrow} Pdt

Hence, rate law for the given reaction will be as follows.

                   Rate = kP_{x}

where,           k = rate constant

                P_{x} = initial pressure of the pollutant X

It is given that, P_{i} =  initial partial pressure of X = 0.473 atm

                        P_{f} =  final partial pressure of X = 0.376 atm

                         Time = 5.6 hours

Hence, formula for rate constant of first order reaction is as follows.

                k = \frac{1}{t} ln(\frac{P_{i}}{P_{f}}

                   = \frac{1}{5.6} ln(\frac{0.473}{0.376})

                   = 0.041 per hour

Therefore, rate of decomposition will be calculated as follows.

              Rate = \frac{dP}{dt} = kP_{i}

                       = 0.041 hr^{-1} \times 0.473 atm

                       = 0.019 atm hr^{-1}

Thus, we can conclude that initial rate of decomposition of X is 0.019 atm hr^{-1}.

7 0
3 years ago
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