What is the y-Intercept of the line that is perpendicular to the line y=3/5+10 and passes through the point (15,-5)?

Mathematics

1 answer:

Nady [450]3 years ago

3 0

Answer:

Y = 3/5x + 10...slope here is 3/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So we need a slope of -5/3

Step-by-step explanation:

y = mx + b

slope(m) = -5/3

(15,-5)...x = 15 and y = -5

now we sub for b, the y int

-5 = -5/3(15) + b

-5 = -25 + b

-5 + 25 = b

20 = b

so ur perpendicular equation is : y = -5/3x + 20

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