Well brake 7 into 5 and 2 and then just multiply it by 3 so it would be 5 x3=15 and 2x3=6 then u add 15+6 it would be the sum, of 21 so 3x7=21
Read the question carefully: it costs 4 tokens to park in a garage for an hour.
We will apply the unitary method to solve this question
It costs 4 tokens to park in a garage for 1 hour
Find how many hours can park in a garage for 1 token
If it costs 4 token to park in a garage for 1 hour
Then it will cost 1 token to park in a garage for 1/4 hour
Step2:
With 20 token we can park in a garage for (1/4) * 20
= 5 hours
So, we can park for 5 hours with 20 tokens.
Another method
If we take twenty tokens and divide them into groups of four, we will find that we are left with five groups of tokens. Each group of tokens represents an hour of parking time. This will give us five groups, or five hours, total.
So, we can park for 5 hours with 20 tokens
Answer:
The third one
Step-by-step explanation:
You would first mark -2 on a graph then the circle would be open because the sign is just greater than, then the arrow would be pointing to the right, because that is the way your equation shows it
Answer:
Minimum 66 feet of molding that he needs.
Step-by-step explanation:
Given that a square ceiling has a diagonal of 23 ft.
If the sides of the square ceiling are 'a' feet, then applying Pythagoras Theorem we can write, a² + a² = 23²
⇒ 2a² = 23²
⇒ a = 16.2634 feet (Approximate)
Now, the perimeter of the square ceiling will be 4a = 65.05 feet.
If the cost of molding along the perimeter of the ceiling is in per foot, then a minimum of 66 feet of molding that he needs. (Answer)
