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3 years ago

Are these correct? If not help me please??

Mathematics

2 answers:

Verizon [17]3 years ago

3 0

Answer: no, no, yes, no, yes, yes

Step-by-step explanation:

x + 1, 2x, these are not equivalent

10x, 5(x+5)

5(x+5) distribute the 5 to get 5(x+5) = 5x + 25

5x + 25 is not equal to 10x, so no

1 + 2x = 2x + 1, these are equivalent since the constant and coefficients are the same

yes

2x, 2x - 5, these are not equivalent since once has a constant of -5 while the other does not

15x -1, 3(x+4x) - (3-2)

3(x+4x) - (3-2) combine like terms

3(5x) - (1) multiply through parentheses

= 15x -1

so 15x - 1 = 3(x+4x) - (3-2), these are equivalent

yes

1/2 * (4x-2),2x-1

1/2 * (4x-2) multiply through parentheses to get

2x - 1

so these two are equivalent

yes

Roman55 [17]3 years ago

3 0

The answer #2 is no and the number #5 is yes.

#2 is no, as you cannot add or subtract if they are not similar. Since in the second part the answer is 5x + 25.

#5 is yes because when there is a subtraction in front of a parenthesis, expressions within the parenthesis must change their sign.

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The number of exports is shown as g(x). Use the data in the table below, representing both functions, to explain to your boss th

siniylev [52]

Step-by-step explanation:

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3 0

3 years ago

Find the A.P whose second term is 12 and 7th term exceeds the 4th by 15

Art [367]

The 2nd term exists 12 and 7th term exceeds the 4th by 15 exists AP : 7,12,17,....

<h3>How to estimate the arithmetic progression?</h3>

Given : The second term exists 12th and the 7th term exceeds the 4th term by 15

The formula of the nth term :

$$a_{n}=a+(n-1) d$

Where d exists a common difference

n be the number of terms

a be the first term

Substitute the value of n = 2

$$a_{2}=a+(2-1) d=a+d$

Let, the second term exists 12

So, a + d = 12 ..........(1)

Substitute the value of n = 7

$$a_{7}=a+(7-1) d=a+6 d$

Substitute n = 4

$$a_{4}=a+(4-1) d=a+3 d$

We are given that the 7th term exceeds the 4th term by 15

So, a+6d-a-3d = 15

3d = 15

d = 5

Substitute the value of d in (1)

So, a+5 = 12

a = 12-5

a = 7

AP : a,a+d,a+2d,.... = 5, 7+5, 7+2(5),....=7,12,17,....

Therefore, AP : 7,12,17,....

To learn more about arithmetic progression refer to:

brainly.com/question/24191546

#SPJ9

4 0

2 years ago