Find value of each variable.

132891 round the nerast hundred

Andrej [43]

Pretty sure that 132,891 rounded to the nearest hundred is 132,900

5 0

3 years ago

Determine the intercepts of the line that passes through the following points

shepuryov [24]

Answer:

(2,0) - x -intercept

(0, 1.5) - y-intercept

Step-by-step explanation:

The slope of the points can be found by writing a ratio of vertical change to horizontal change. It can be found in the table by subtracting y values from each other and subtracting x values from each other. The y values decrease by 3 each time or -6 - -3 = -6 + 3 = -3.

The x values increase by 4.

So the rate of change is -3/4.

This means if you go backwards on the table the previous point would be (2, 0). This is the x-intercept.

To find the y-intercept, you must go further back. Going back 2 more units would make the table appear as:

x y

-2 3

0 ???

2 0

6 -3

10 -6

14 -9

Since the y values decrease by 3 each time and we went back half the usual amount, then the value would be 1.5.

5 0

3 years ago

I'll give you brainliest or something just help.

irga5000 [103]

Answer:

C=25 (vertically opposite angle)

b=150 (linear pair)

d=150(vertically opposite angle)

Step-by-step explanation:

pls mark BRAINLIEST

3 0

2 years ago

The function f(x) varies inversely with x and f(x)=2 when x = 16.<br><br> What is f(x) when x = 4?

andrew-mc [135]

Answer: The correct answer is: [D]: "8" .

Step-by-step explanation:f y varies inversely with x; then y = k/x ; with "k" being the "constant" in this equation.

You can find the constant by substituting the values given: x = 16, f(x) = y = 2 ;

So, f(x) = y = 2 = k/16 ;

→ 2 = k / 16 ;

Solve for the constant; "k" ;

Multiply EACH SIDE of the equation by "16"

→ 16* (2) = (k / 16) * 16 ;

→ 32 = k ;

↔ k = 32 ;

As such, we can write the equation:

y = k/ x ; as:

→ y = 32/ x ;

Since we are given: "x = 4" ; Plug in that value; and solve for "y" ;

y = 32/4 = 8 .

y = 8 .

y = f(x) ;

So; f(x) = 8 ; which is: Answer choice: [D]: "8" .

8 0

2 years ago

The time a randomly selected individual waits for an elevator in an office building has a uniform distribution with a mean of 0.

Amiraneli [1.4K]

Answer:

The mean of the sampling distribution of means for SRS of size 50 is $\mu = 0.5$ and the standard deviation is $s = 0.0409$

By the Central Limit Theorem, since we have of sample of 50, which is larger than 30, it does not matter that the underlying population distribution is not normal.

0% probability a sample of 50 people will wait longer than 45 seconds for an elevator.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size, of at least 30, can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 0.5, \sigma = 0.289$

What are the mean and standard deviation of the sampling distribution of means for SRS of size 50?

By the Central Limit Theorem

$\mu = 0.5, s = \frac{0.289}{\sqrt{50}} = 0.0409$

The mean of the sampling distribution of means for SRS of size 50 is $\mu = 0.5$ and the standard deviation is $s = 0.0409$

Does it matter that the underlying population distribution is not normal?

By the Central Limit Theorem, since we have of sample of 50, which is larger than 30, it does not matter that the underlying population distribution is not normal.

What is the probability a sample of 50 people will wait longer than 45 seconds for an elevator?

We have to use 45 seconds as minutes, since the mean and the standard deviation are in minutes.

Each minute has 60 seconds.

So 45 seconds is 45/60 = 0.75 min.

This probability is 1 subtracted by the pvalue of Z when X = 0.75. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.75 - 0.5}{0.0409}$

$Z = 6.11$

$Z = 6.11$ has a pvalue of 1

1-1 = 0

0% probability a sample of 50 people will wait longer than 45 seconds for an elevator.

8 0

3 years ago