John J. Parker worked 44 hours this week. He gets time-and-a-half for any hours beyond 40.
1 answer:
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See the picture attached to better understand the problem
we know that
a full circle is a 360 degrees
divided in 12 equals parts-------> 360/12-------> 30 degrees each part
<span>the smallest angle formed by the hands of a clock at 7 o'clock has 5 parts
so
5*30</span>°------> 150°
convert to radian
pi radians---------> 180°
x ---------------> 150°
x=150*pi/180--------> x=0.83*pi radians
the answer is
0.83*pi radians or 2.62 radians
we know that
a full circle is a 360 degrees
divided in 12 equals parts-------> 360/12-------> 30 degrees each part
<span>the smallest angle formed by the hands of a clock at 7 o'clock has 5 parts
so
5*30</span>°------> 150°
convert to radian
pi radians---------> 180°
x ---------------> 150°
x=150*pi/180--------> x=0.83*pi radians
the answer is
0.83*pi radians or 2.62 radians
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
