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brilliants [131]
2 years ago
6

Christopher deposited $1 in a savings account earning

Mathematics
2 answers:
ololo11 [35]2 years ago
8 0

Answer:$1.33

Step-by-step explanation: I did the math myself and i would say yes the person above is correct you should give him brainliest...

andriy [413]2 years ago
6 0

Answer: He would have $1.33 after 3 years glad to help please mark brainliest!

Step-by-step explanation:

using simple interest formula: A = P(1 + r)^t

A= Total amount in 3 years

P=starting total

r=rate of percent as a decimal

t=time in years

A=1(1+0.10)^3

A=1(1+0.10)^3

A=1(1.10)^3

A=1(1.331)

A=1.331

A=1.33

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O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
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Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

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Step-by-step explanation:

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Step-by-step explanation:

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