Let us assume that if possible in the group of 101, each had a different number of friends. Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends. In this case, there cannot be any one who has 0 friend. So a contradiction. Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

if different number of friends then they would be 0,1,2...n-1

If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

7 0

3 years ago

2. What type of angle is ACE? right acute obtuse straight

cestrela7 [59]

It is a straight angle because it is on a straight line.

Hope this helps :)

3 0

3 years ago

Read 2 more answers

There are 10 large fish and 5 small fish. Half of the large fish are red. One fish is selected at random. Find the probability t

Softa [21]

The probability of choosing a large red fish is 5/15 or 1/3

3 0

3 years ago