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julia-pushkina [17]
3 years ago
9

A chemist observed an unknown Balmer Series decay through an emission of 410 nm. Using the experimental wavelength, determine th

e energy levels transition involved in the
emitted wavelength.

Chemistry
1 answer:
Genrish500 [490]3 years ago
7 0

Answer:

Option D is correct.

n = 6 to n = 2

Explanation:

Like all waves emitted from the movement of electrons from one energy level to another, the wavelength (λ) is given by the equation involving Rydberg's constant

(1/λ) = Rₕ [(1/n₂²) - (1/n₁²)]

where Rₕ = 10973731.57 m⁻¹ = (1.0974 × 10⁷) m⁻¹

n₂ = principal quantum number corresponding to the final energy level of the electron = 2 (For Balmer Series)

n₁ = principal quantum number corresponding to the final energy level of the electron = ?

λ = 410 nm = (410 × 10⁻⁹) m

(1/λ) = (2.439 × 10⁶) m⁻¹

2.439 × 10⁶ = (1.0974 × 10⁷) [(1/2²) - (1/n₁²)]

0.25 - (1/n₁²) = (2.439 × 10⁶) ÷ (1.0974 × 10⁷) = 0.2222602562

(1/n₁²) = 0.25 - 0.2222602562 = 0.0277397438

n₁² = (1/0.0277397438) = 36.05

n₁ = 6

Hope this Helps!!!

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Answer:

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____________________________

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6 0
3 years ago
Chuck wants to know how many electrons in an atom are not paired up. Which model would be best for Chuck to
loris [4]

Answer:

D. an orbital notation of the atom

Explanation:

Orbital notiation uses lines and arrows to show shells, subshells, and orbitals for electrons in an atom. Since it shows arrows being paired up in this diagram it would be the best model for Chuck to use.

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Which statement describes a system that consists of sugar crystals dissolving in water?
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To know the answer, you either know what is really the nature and chemistry of a sugar solution. You can also know the answer by knowing the meaning of entropy. Entropy is often interpreted as the degree of disorder or randomness in the system. So the correct statement is that the system becomes more disordered and has an increase in entropy.

7 0
3 years ago
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Hydrogen gas and fluorine gas will react to form hydrogen fluoride gas. What is the standard free energy change for this reactio
Marta_Voda [28]

Answer:

\Delta G=-541.4kJ/mol

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write out the described chemical reaction as shown below:

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Now, we set up the expression for the calculation of the standard free energy change, considering the free energy of formation of each species, specially those of H2 and F2 which are both 0 because they are pure elements:

\Delta G=2\Delta G_f^{HF}-(\Delta G_f^{H_2}+\Delta G_f^{F_2})\\\\\Delta G=2*-270.70kJ/mol-(0kJ/mol+0kJ/mol)\\\\\Delta G=-541.4kJ/mol

Regards!

4 0
3 years ago
C. identify a set of four possible quantum numbers for the circled electron in manganese (mn). (there is more than one correct a
steposvetlana [31]
Although you have not provided the circled electron, I can help you with a wide explanation.

1) Atomic number of manganese is 25. That means that it has 25 protons and 25 electrons.

2) Those 25 electrons are distributed (electron configuration) as per the quantum rules:

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3) The most reasonable is that you have been asked to give the possible quantum numbers for an electron in the 4s or 3d.

4) Those are 7 electrons and these are their possible sets of quantum numbers:
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l tells the kind of orbital, which is s, so l = 0
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ms: one is +/12 and the other is -1/2 (this is the spin number).


ii) For the 5 electrons in 3d

n = 3
l can be 0, 1, or 2
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if l = 1, then ml can be -1, 0 , or 1 (from - l to + l)


ms can be either +1/2 or - 1/2 (spin)
5 0
3 years ago
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