The general equation for radioactive decay is;
N = N₀e^(-λt)
x - decay constant (λ) - rate of decay
t- time
N - amount remaining after t days , since we are calculating the half life, amount of time it takes for the substance to to be half its original value, its N₀/2
N₀ - amount initially present
substituting the values
N₀/2 = N₀e^(-0.081t)
0.5 = e^(-0.081t)
ln (0.5) = -0.081t
-0.693 = -0.081t
t = 0.693 / 0.081
= 8.55
half life of substance is 8.55 days
Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits is mathematically given as
N=1820slits
<h3>What minimum number of slits is required to resolve these two wavelengths in second-order?</h3>
Generally, the equation for the wave is mathematically given as
Where the chromatic resolving power (R) is defined by
R = nN,
Therefore
and
In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order
Therefore
N=1820slits
Read more about slits
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No. Although two such atoms are essentially chemically identical (they will chemically react in the same way), they are not completely identical.
Answer: Igneous rocks may be simply classified according to their chemical/mineral composition as felsic, intermediate, mafic, and ultramafic, and by texture or grain size: intrusive rocks are course grained (all crystals are visible to the naked eye) while extrusive rocks may be fine-grained (microscopic crystals) or glass.
Explanation: Hope this helped! :)
Answer:
Radioactive isotopes ranging from 11O to 26O have also been characterized, all short-lived. The longest-lived radioisotope is 15O with a half-life of 122.24 seconds, while the shortest-lived isotope is 12O with a half-life of 580(30)×10−24 seconds (the half-life of the unbound 11O is still unknown).
