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3 years ago

8

I need help with this question? Please and thank you!!!! #15

2 answers:

Alecsey [184]3 years ago

8 0

Answer:

sorry i don't understand it

4vir4ik [10]3 years ago

7 0

Ref3vygrnvrgnubub frrrrrrrrvcrf

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Solve for x.<br> Please helppp

tankabanditka [31]

Answer:

x = 23

Step-by-step explanation:

2x + 19 + 5x = 180

I say this because it is an angle that is equivalent to the one adjacent to 2x+19, which is on a straight line. That means it is equal to 180.

7x + 19 = 180

180 - 19 = 7x

161/7 = x

x = 23

4 0

2 years ago

Read 2 more answers

If SU and VX are parallel lines and mUTW = 131°, what is mVWT?

TiliK225 [7]

<u>Answer:</u>

∠VWT = 131°

<u>Explanation:</u>

∠VWT is equal to ∠UTW because they are Alternate inner angles. Since they are equal, we know that the measure of ∠VWT is 131°.

Hoped this helped!

4 0

2 years ago

Need help on these trig homework

allochka39001 [22]

8. The length of the support is 7. 9 m

9. The length of the conveyer is 12m

3. a = 59m

A = 44°

B = 52°

4. c = 88. 6 mm

b = 49. 1 m

B = 34°

<h3>How to solve the trigonometry</h3>

8. We have the angle to be 20 degrees

Opposite side = x

hypotenuse = 23m

Using the sine ratio

sin θ = opposite/ hypotenuse

$sin 20 = \frac{x}{23}$

Cross multiply

$sin 20$ × $23 = x$

$x = 0. 3420$ × $23$

x = 7. 9 m

The length of the support is 7. 9 m

9. The angle of elevation is 37. 3 degrees

Hypotenuse = 19 . 0m

Opposite = x

Using the sine ratio

sin θ = opposite/ hypotenuse

$sin 37. 3 = \frac{x}{19}$

cross multiply

$x = 0. 6059$ × $19$

x = 11.5

x = 12 m in 2 significant figures

The length of the conveyer is 12m

3. To determine the sides and angles, we use the sine rule;

$\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}$

For side a, we use the Pythagorean theorem

$c^2 = a^2 + b^2$

$85^2 = a^2 + 67^2$

$a = \sqrt{89^2-67^2}$

$a = \sqrt{3432}$

a = 58. 58, a = 59m

To find angle A and B, use the sine rule

$\frac{59}{sin A } = \frac{85}{sin 90}$

cross multiply

$sin A$ × $85$ = $sin 90$ × $59$

make sin A subject of formula

$sin A = \frac{59}{85}$

$sin A = 0. 6941$

A = $sin^-^1(0. 6941)$

A = 44°

$\frac{67}{sin B} = \frac{85}{sin 90}$

cross multiply

$sin B$ × $85$ = $sin 90$ × $67$

make sin b subject of formula

$sin B = \frac{67}{85}$

$sin B = 0. 7882$

B = $sin^-^1( 0. 7882)$

B = 52°

4. To find the sides, we use the sine rule;

$\frac{74. 0}{sin 56. 6} = \frac{c}{sin 90}$

Cross multiply

$sin 56. 6$ × $c = sin 90$ × $74$

make 'c' subject of formula

$c = \frac{74}{0. 8348}$

c = 88. 6 mm

To find length b, we use the Pythagorean theorem

$c^2 = a^2 + b^2$

$b^2 = c^2 - a^2$

$b^2 = 88. 8^2 - 74^2$

$b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}$

b = 49. 1 m

$\frac{74. 0}{sin 56. 6} = \frac{49. 1}{sin B}$

cross multiply

$sin B = \frac{40. 99}{74. 0}$

B = $sin^-^1(0. 5539)$

B = 34°

Learn more about trigonometric identity here:

brainly.com/question/7331447

#SPJ1

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1 year ago

PLEASE HELP Which was a belief of the early Democratic-Republican Party? The United States should have a conservative foreign po

Studentka2010 [4]

Answer:

C. Should not have a bank

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3 years ago

PLEASE HELP. Write the equation in slope-intercept form for the line that contains the points

madam [21]

Answer:

y=2x-11

Step-by-step explanation:

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3 years ago