Answer:
dhbsugubihsvhukejbduisxkgdbwq
Step-by-step explanation:
iwdyhbjksgcsbhhsnnsgdhhsns
Answer:
108 cm cubed
Step-by-step explanation:
(1/2 of length•height)•width
(1/2 of 6•4)•9
(1/2 of 24) •9
12•9
108
2.5 is already rounded to the nearest hundredth. S it cant be rounded again. Its already rounded by the nearest hundredth.
hope it helps!
The answer is C
Because you have to add them all up. So add the 1/3 and 2/3 which equals 3/3 which is equal to 1. So then you add the 1/6 which equals 2/6 which is equivalent to 1/3 then you add that 1/3 to the last 1/3 which also equals 2/6 and as we established that equals 1/3 so the answer is 1 and 1/3.
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of ![x = \sqrt[3]{29}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B29%7D)
(cube root of 29) and the other two roots are complex or imaginary roots.
