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3 years ago

How to slove - Tan x°= 1.11 and what is the answer?

1 answer:

5 0

$\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides}
\\\\\\
tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)$

plug that in your calculator, make sure the calculator is in Degree mode

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Please please help me

miskamm [114]

Answer:

$3 {x}^{2} - 2x + 1$

$now \: \: x = 4$

$3 {(4)}^{2} - 2(4) + 1$

$3(16) - 8 + 1$

$48 - 8 + 1 = 41$

41 is the answer

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1 year ago

What’s the difference please help

labwork [276]

Answer:

C: $-7ab \sqrt[3]{3ab^{2} }$

Step-by-step explanation:

Simplify or expand:

$2ab\sqrt[3]{192ab^{2} } - 5\sqrt[3]{81a^{4} b^{5} }$

Transform the expression:

$2ab\sqrt[3]{4^{3}*3ab^{2} }$ - $5\sqrt[3]{3^{3}*3a*ab^{3} b^{2} }$

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Combine like terms.

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1 year ago

What will it cost to buy a rectangular window with a length of 10ft and a width of 13ft? The cost per square foot for this type

Bad White [126]

Answer:i need points

Step-by-step explanation:

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2 years ago

Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p

zubka84 [21]

Answer: The required answers are

(a) 0.25, (b) 0.62, (c) 6.

Step-by-step explanation: Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

$P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.$

(a) The probability of getting 5 heads is given by

$P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.$

(b) The probability of getting 5 or more than 5 heads is

$P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.$

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

$P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.$

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0

3 years ago

Which choice represents the fraction below as a single exponential

Vladimir [108]

Answer:

8^5

Step-by-step explanation:

division is just minusing exponents

4 0

1 year ago

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