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AysviL [449]
3 years ago
9

Which statement is true about the end behavior of the

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

End behavior :

1. As the x-values go to positive infinity, the function's values go to negative infinity

2. As the x-values go to negative infinity, the function's values go to positive infinity.

Option D: f(x) over the interval (-4,\infty).  (answer for question in image)

Step-by-step explanation:

From the given graph it is clear that as the x-values go to positive infinity, the function's values go to negative infinity and as the x-values go to negative infinity, the function's values go to positive infinity.

It means,

f(x)\rightarrow -\infty\text{ as }x\rightarrow \infty

f(x)\rightarrow \infty\text{ as }x\rightarrow -\infty

At x=0, the value of function is -3.

Note: All options are incorrect for end behavior.

From the given graph it is clear that the function is above the x-axis before -4 and after that it is below the x-axis. So,

f(x)>0 over the interval (-\infty, -4).

f(x) over the interval (-4,\infty).

Therefore, the correct option is D.

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balu736 [363]
Hello,

y=x²-25
==>x=y²-25 ==>y=±√(x+25)


Answer B: ±square root of the quantity x plus 25



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3 years ago
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You order from a catalog the following office supplies: 10 boxes of paper, each box is 6 pounds and 36 boxes of pens, each box w
zhannawk [14.2K]
10x6=60 pounds
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60+27=87
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4 years ago
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An auto company claims that the fuel efficiency of its sedan has been substantially improved. A consumer advocate organization w
zzz [600]

Answer:

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.983 -0}{\frac{1.685}{\sqrt{12}}}=2.021

df=n-1=12-1=11

p_v =P(t_{(11)}>2.021) =0.0342

If we compare the the p value with the significance level provided \alpha=0.1, we see that p_v < \alpha, so then we can reject the null hypothesis. and there is a significant increase in the miles per gallon from 2017 to 2019 at 10% of significance.

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

Let put some notation :

x=test value 2017 , y = test value 2019

x: 28.7 32.1 29.6 30.5 31.9 30.9 32.3 33.1 29.6 30.8 31.1 31.6

y: 31.1 32.4 31.3 33.5 31.7 32.0 31.8 29.9 31.0 32.8 32.7 33.8

Solution to the problem

The system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x \leq 0

Alternative hypothesis: \mu_y -\mu_x >0

Because if we have an improvement we expect that the values for 2019 would be higher compared with the values for 2017

The first step is calculate the difference d_i=y_i-x_i and we obtain this:

d: 2.4, 0.3, 1.7,3,-0.2, 1.1, -0.5, -3.2, 1.4, 2, 1.6, 2.2

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{11.8}{12}=0.983

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.685

We assume that the true difference follows a normal distribution. The 4th step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.983 -0}{\frac{1.685}{\sqrt{12}}}=2.021

The next step is calculate the degrees of freedom given by:

df=n-1=12-1=11

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(11)}>2.021) =0.0342

If we compare the the p value with the significance level provided \alpha=0.1, we see that p_v < \alpha, so then we can reject the null hypothesis. and there is a significant increase in the miles per gallon from 2017 to 2019 at 10% of significance.

4 0
3 years ago
PLEASE ANSWER, I HAVE A QUIZ THAT NEEDS TO GET DONE AND I HAVE NO IDEA HOW TO GET THIS!
Oliga [24]
There you go. cube root of smth is just the value to the power of one third.

4 0
3 years ago
The length of a rectangular frame is 8 cm more than the width. The area inside the frame is 65 square cm. Find the width of the
fgiga [73]
L+8=W
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sub W from the first equation to second one
L*(L+8)= 65
L^2+8L =65   L^2+8L -65 =0  L=-13 and L=5, length cannot be negative so L=5 is the answer
sub this value in the first equation W=13
8 0
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