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3 years ago

Calculate the partial sum S for the sequence 243,81,27,....

Mathematics

2 answers:

Murrr4er [49]3 years ago

8 0

Answer:

D. 363 is the one

Llana [10]3 years ago

4 0

Answer:363

Step-by-step explanation:

We have to find partial sum for the sequence 243 , 81 , 27 ..... up to 5 terms(S5 given)

The sequence actually is 3^5,3^4.,3^3.....

Therefore first 5 terms are 1) 3^5 I.e. 243

2) 3^4 I.e. 81

3) 3^3 I.e. 27

4)) 3^2 I.e. 9

5) 3^1 I.e. 3

Adding all those no. we get partial sum of first 5 no. of the sequence

So, 243 + 81 + 27 + 9 + 3

= 363

Hope it helps!!!

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Arlecino [84]

Answer:

It will take <em>0.75 hours </em>to Russell catch Gertrude

Step-by-step explanation:

<u>Cinematics</u>

The equations of cinematics include velocity, displacement and time. In case only the magnitudes are important, we can use the concepts of speed and distance. The speed can be thought in relative terms, i.e. if one body moves at 10 m/s and other moves at 8 m/s, we can say the relative speed is 2 m/s.

The equation who relates those magnitudes is

$x=vt$

The problem states Gertrude travels at 10 mph and is 3 miles ahead of Russell who travels at 14 mph. We want to know the time when Russell will catch Gertrude. Since Russell goes faster than Gertrude, he eventually catches her. In a time t, he must travel 3 miles more than her. Since the relative speed of them is 14-10= 4 mph, we can know the time it takes to the encounter to produce

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Answer: It will take 0.75 hours to Russell catch Gertrude

4 0

3 years ago

WILL GIVE BRAINLIEST

IrinaK [193]

Part one:

$x^2-8x=-26$

Rewrite in the form $(x+a)^{2} =b$

$\left(x-4\right)^2=-10$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

Solve $x-4=\sqrt{-10} : x=\sqrt{10} i+4$

Solve $x-4=\sqrt{-10} : x=-\sqrt{10} i+4$

$x=\sqrt{10}i+4,\:x=-\sqrt{10}i+4$

Part two:

$x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}{2\cdot \:1}$

Simplify $\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}: 2\sqrt{10} i$

$=\frac{-\left(-8\right)\pm \:2\sqrt{10}i}{2\cdot \:1}$

Separate solutions

$x_1=\frac{-\left(-8\right)+2\sqrt{10}i}{2\cdot \:1},\:x_2=\frac{-\left(-8\right)-2\sqrt{10}i}{2\cdot \:1}$

$\frac{-(-8)+2\sqrt{10}i }{2*1} :4+\sqrt{10}i$

$\frac{-(-8)+2\sqrt{10}i }{2*1} :4-\sqrt{10}i$

$x=4+\sqrt{10}i,\:x=4-\sqrt{10}i$

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Answer:

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gogolik [260]

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Step-by-step explanation:

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3 years ago

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