Equation of the parabola: y = ax^2 + bx + c. Find a, b, and c. x of axis of symmetry: x = − b 2 a = 3 -> b = -6a Writing that the graph passing at point (1, 0) and point (4, -3): (1) 0 = a + b + c -> c = - a - b = - a + 6a = 5a (2) -3 = 16a + 4b + c --> -3 = 16a - 24a + 5a = -3a --> a = 1 b = -6a = -6; and c = 5a = 5 y = x 2 − 6 x + 5
