Question

A punter on Westview High School's football team kicks a ball straight up from 5 feet above the ground with an initial upward velocity of 45 feet per second. The height of the ball above ground after t seconds is given by the equation h = –16t2 + 45t + 5, where h is the height of the ball in feet and t is the time in seconds since the punt. What is the maximum height of the ball, to the nearest foot?

Answer 1

Answer: A. 37 feet

Step-by-step explanation:

1. You can find the x value of the vertex of the parabola as following:

$x=-\frac{b}{2a}$

2. Substitute values:

a=-16

b=45

 $x=-\frac{45}{2(-16}$

$x=1.40$

3. Substitute the vaue obtained into the equation given in the problem. Therefore, you obtain the following result:

$h=-16(1.40)^{2}+45(1.40)+5\\h=36.64$

4. To the nearest foot:

$h=37ft$