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Usimov [2.4K]
3 years ago
6

A company packs 36 boxes in each case to ship to stores. You have been assigned the task to determine the least amount of volume

required to hold 36 boxes. Explain how you arrived at your answer.
The volume of each box is 12 in^3
Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

432 in^3.

Step-by-step explanation:

The volume of each individual box is 12 cubic inches. 12 × 36 = 432 cubic inches. The case needs to hold at least 432 in^3.

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Light travels about 186,000 mi/s, the function d(t)=186,000 gives the distance in miles that light travels in T seconds , how fa
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Light travels 5,580,000 mi/s in thirty seconds
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3 years ago
A rancher wishes to build a fence to enclose a rectangular pen having area 24 square yards. Along one side the fence is to be ma
Gnoma [55]

Answer:

The  value  is  C \approx \$76

Step-by-step explanation:

From the question we are told that

   The  area of the rectangular pen is  A =  24 \ yard^2

     The  cost of material used to make one side is  z = \$ 6

    The  cost of material used to make the other sides is  r  =  \$ 3

Now  , the fence to be build around the rectangular pen  has four sides, the first opposite sides are equal, let assume each of the to be x yard   and the other opposite sides are also equal as well let assume of the to be y yard

So the cost is mathematically represented as

       C =  zx  +  r (x + 2y )

=>   C =  6x  +  3(x + 2y)

=>   C =   9x  +  6y

Now the area of the fence is mathematically represented as

      A =  x* y =  24

=>    y  =  \frac{24}{x}

=>  C =   9x  +  6[\frac{24}{x} ]

=>   C =   9x  +  [\frac{144}{x} ]

Now differentiating

     C'  =  9 + 144*  (-2) x^{-2}

     C'  =  9 - 288x^{-2}

At minimum C' =  0

So  

     9 - 288x^{-2} =  0

     x^{-2} =  0.03125

    x =  \sqrt{\frac{1}{0.03125} }

    x =  5.66

Now substituting for x in the equation above to obtain minimum cost

       C =   9(5.66)  +  [\frac{144}{5.66} ]

       C \approx \$76

   

 

8 0
3 years ago
What is the caputal of idaho
zavuch27 [327]

Capital of Idaho is boise this is not a math question

5 0
3 years ago
Read 2 more answers
The sum of three numbers is 11 . The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is
Assoli18 [71]

Answer:

4, 6, 1

Step-by-step explanation:

We can solve this problem using a system of equations:

1) a + b + c = 11

2) 2a + 5b + 6c = 44

3) 4a - b = 10

First, we can substitute the value of b from equation #3 into equation #1:

b = 4a - 10

a + (4a - 10) + c = 11

5a - 10 + c = 11

5a + c = 21

c = 21 - 5a

Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:

2a + 5(4a - 10) + 6(21 - 5a) = 44

2a + 20a - 50 + 126 - 30a = 44

-8a + 76 = 44

-8a = -32

a = 4

b = 4a - 10 = 4(4) - 10 = 6

c = 21 - 5a = 21 - 5(4) = 1

4 0
2 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER. Find the values of
soldier1979 [14.2K]

Step-by-step explanation:

I am not sure this is a square.

this could be a rectangle.

to be safe, I am following that path.

in a rectangle opposite sides are of equal length.

that means

y - 1 = 2y - 7

y = 2y - 6

0 = y - 6

y = 6

3x - 4 = 3y - 13

3x - 4 = 3×6 - 13

3x - 4 = 18 - 13 = 5

3x = 9

x = 3

as it turns out, it is a square, so we could have used every side expression to be equal with every other side expression, but better safe than sorry ...

5 0
2 years ago
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