a group buys 6 hot dogs and 3 hamburgers for a total of $27.75. the hamburgers cost $1.75 more than a hot dog. what is he cost o
1 answer:
Answer:
Cost of one hamburger = $4.25
Step-by-step explanation:
Let,
Cost of one hot dog = x
Cost of one hamburger = y
According to given statement;
6x + 3y = 27.75 Eqn 1
y = x + 1.75 Eqn 2
Putting value of y from Eqn 2 in Eqn 1
6x + 3(x+1.75) = 27.75
6x + 3x + 5.25 = 27.75
9x = 27.75 - 5.25
9x = 22.50
Dividing both sides by 9
Putting x=2.50 in Eqn 2
y = 2.50 + 1.75
y = 4.25
Hence,
Cost of one hamburger = $4.25
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Answer:
we choose f(x) = π cos(πx)
Step-by-step explanation:
Given the information:
- f(0) = 0
- f(2) = π
Let analyse all possible answers;
1/ f(x) = -2 sec(x)
when x= 0 we have: f(0) = -2 sec(0) = -2 = -2 wrong
2. f(x) = 7sin(x/4 - 1/29)
when x= 0 we have: f(0) =7sin(0/4 - 1/29) = 7sin(-1/29) = -0.00421 wrong
3. (x) = π cos(πx)
when x= 0 we have: f(0) = πcos(π0) = cos(0) = π0 = 0
when x= 2 we have: f(2) = πcos(π2) = πcos(0) = π
True
4. f(x) = 2π cos(x - π/2)
when x= 0 we have: f(0) = 2π cos(0 - π/2) = 2π cos(-π/2) = 0
when x= 2 we have: f(2) =2π cos(2 - π/2) = 2π0.034 = 0.0697π Wrong
So we choose f(x) = π cos(πx)
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