a group buys 6 hot dogs and 3 hamburgers for a total of $27.75. the hamburgers cost $1.75 more than a hot dog. what is he cost o
1 answer:
Answer:
Cost of one hamburger = $4.25
Step-by-step explanation:
Let,
Cost of one hot dog = x
Cost of one hamburger = y
According to given statement;
6x + 3y = 27.75 Eqn 1
y = x + 1.75 Eqn 2
Putting value of y from Eqn 2 in Eqn 1
6x + 3(x+1.75) = 27.75
6x + 3x + 5.25 = 27.75
9x = 27.75 - 5.25
9x = 22.50
Dividing both sides by 9
Putting x=2.50 in Eqn 2
y = 2.50 + 1.75
y = 4.25
Hence,
Cost of one hamburger = $4.25
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Answer:
Case 1:
Case 2:
Case 3: Not possible
Step-by-step explanation:
Given
See attachment for illustration of each case
Required
Find AB and BC
Case 1:
Using Pythagoras theorem in ANB, we have:
This gives:
Take square roots of both sides
To calculate BC, we consider ANC, where:
Collect like terms
Take square roots
So:
Case 2:
Using Pythagoras theorem in ANB, we have:
This gives:
Collect like terms
Take square roots of both sides
To calculate BC, we consider ABC, where:
Collect like terms
Take square roots
Case 3:
This is not possible because in ANC
The hypotenuse AN (24) is less than AC (40)
