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3 years ago

A=5x+20 B=9x-92 Solve for x and then find the measure of A

Mathematics

1 answer:

Leviafan [203]3 years ago

8 0

Because of the transversal and the parallel lines, we know that A+B=180°.

So:
5x + 20 + 9x - 92 = 180
14x - 72 = 180
14x = 180 + 72
14x = 252
x = 252/14
x = 18

A = 5x + 20
A = 5*18 + 20
A = 90 + 20 = 110

(Let’s check:
B = 9*18 - 92
B = 162 - 92
B = 70
70 + 110 = 180)

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Each of the 25 balls in a certain box is either red, blue, or white and has a number from 1 to 10 painted on it. If one ball is

LekaFEV [45]

Answer: Insufficient Information

The probability of selecting a red ball, a blue ball or a white ball is unknown.

Step-by-step explanation:

The probability of selecting a red ball, a blue ball or a white ball is unknown.

There could be 13 red balls, 1 blue ball and 11 white balls in the bag. There could be 3 red balls, 2 blue balls and 20 white balls in the bag. It is impossible to say with the information given have even numbers on them. The same thing applies to the number of balls with numbers or even numbers on them. The question does not specify how many white balls have each number on them.

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3 years ago

How to represent a negative number in binary?

slega [8]

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3 years ago

Simplify 4n5 + 3.5n5 + (-2.1n5). 4.4 n5 5.4 n5 20 n5 6.4 n5

ella [17]

Answer:

$4 {n}^{5} + 3.5 {n}^{5} + ( - 2.1 {n}^{5} )$

first create a bracket:

$= ( {4n}^{5} + 3.5 {n}^{5} ) + ( - 2.1 {n}^{5} )$

then solve the first bracket:

$= {7.5 {n}^{5} } + ( - 2.1 {n}^{5} )$

then open the remaining bracket:

$= {7.5n}^{5} - {2.1n}^{5}$

carryout the subtraction operation:

$= (7.5 - 2.1) {n}^{5} \\ { \boxed{ = {5.4n}^{5} }}$

7 0

3 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

2 years ago

Inez Walks 1.85 mi in 45 minutes , how many miles can she walk in 1 hour?

insens350 [35]

Answer:

She can walk 2.46 repeating miles in 1 hour

Step-by-step explanation:

We can write a proportion to solve this problem. Write the number of miles on top and the time in minutes on the bottom. We know 1 hour is 60 minutes.

1.85 miles x miles

------------------- = ----------------------

45 miles 60 minutes

Using cross products

1.85 * 60 = 45x

Divide each side by 45

1.85*60/45 = 45x/45

2.466666666 =x

She can walk 2.46 repeating miles in 1 hour

4 0

2 years ago