F: R -> R, f(x) = ax + b;
f(1) = 8 => a + b = 8;
f(2) = 14 => 2a + b = 14 => a = 6 and b =2;
f(3) = 20 => 6*3 + 2 = 20 True;
f(4) = 26 => 4*6 + 2 = 26 True;
then, f:R -> R, f(x) = 6x + 2;
Answer:
Let L be the length of the rectangle and w be the width of the rectangle.
"The lenght of a rectangle is one less than twice the width" means L=2W-1
Using perimeter formula of a rectangle which is P=2(L+W) you have:
P=2(L+W)
130=2(2W-1+W)
Solve equation above to find W
130=2(3W-1)
130=6W-2
130+2=6W
132=6W
W=22
From here you find L=2W-1=2x22-1=43
Only thing left is to find area A=LxW
Rate x time = distance
25 x 35/60 = distance (35/60 is 35 minutes out of an hour- 60 minutes)
25/1 x 7/12 = distance (I put the 25 over 1 and reduced 35/60)
175/12 ≈ 14.58 miles
Notice that the time had to be in a fraction of an hour in order to do this.
The correct answer is: 11
Here’s how you solve it!
You can remove the 0 since when you add or subtract 0 it stays the same.
Then you would want to look at the first set of parentheses (-20)
Since it is -(-20) this changes the sign to a positive +20
9-5+20+(-13)
Now since the + is in front of the (-13) it remains the same.
Now you are left with this:
9-5+20-13
9-5=4
4+20=24
24-13=11
Then you are left with your answer: 11
Hope this helps! :3
This question is unclear, I don't understand and it doesn't ask the question.
