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zloy xaker [14]

2 years ago

14

Someone helpplz (I'm stressed don't try to get fxree points please)

1 answer:

Sav [38]2 years ago

4 0

here ya go!!! I hope this helps <3

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If cotθ=3/4 and the terminal point determined by θ is in quadrant 3, then: (choose all that apply)

anygoal [31]

With $\theta$ in quadrant 3, we should expect both $\cos\theta$ and $\sin\theta$ to be negative, so that $\tan\theta$ is positive. The corresponding reciprocal expressions $(\sec\theta,\csc\theta,\cot\theta)$ will have the same sign.

$\cot\theta=\dfrac34\implies\tan\theta=\dfrac43$

Recall that $1+\tan^2\theta=\sec^2\theta$ , which means

$\sec\theta=-\sqrt{1+\tan^2\theta}=-\dfrac53$

$\implies\cos\theta=-\dfrac35$

Also recall that $\cos^2\theta+\sin^2\theta=1$ , so

$\sin\theta=-\sqrt{1-\cos^2\theta}=-\dfrac45$

$\implies\csc\theta=-\dfrac54$

Only the first two options are correct.

6 0

2 years ago

Can someone help me with this. Will Mark brainliest.

HACTEHA [7]

Answer: True!

Step-by-step explanation: Rhombuses are like squares with an 4 equivalent sides!

hope this helped have a nice day ! :)

4 0

2 years ago

Read 2 more answers

Find the values of y = c(x) = for x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, , 0.729, and 1.

kondaur [170]

c(x) is a function, then we will solve the problem for two different functions.

1. If $c(x)=\frac{x}{0.5}+x$

Then

$y=c(x)$

$y=\frac{x}{0.5}+x$

Using each of the values for x we have.

When x=0 the result is: $y=\frac{0}{0.5}+0=0$

When x=0.008 the result is: $y=\frac{0.008}{0.5}+0.008=0.016+0.008=0.024$

When x=0.027 the result is: $y=\frac{0.027}{0.5}+0.027=0.054+0.027=0.081$

When x=0.064 the result is: $y=\frac{0.064}{0.5}+0.064=0.128+0.064=0.192$

When x=0.125 the result is: $y=\frac{0.125}{0.5}+0.125=0.25+0.125=0.375$

When x=0.216 the result is: $y=\frac{0.216}{0.5}+0.216=0.432+0.216=0.648$

When x=0.343 the result is: $y=\frac{0.343}{0.5}+0.343=0.686+0.343=1.029$

When x=0.512 the result is: $y=\frac{0.512}{0.5}+0.512=1.024+0.512=1.536$

When x=0.729 the result is: $y=\frac{0.729}{0.5}+0.729=1.458+0.729=2.187$

When x=1 the result is: $y=\frac{1}{0.5}+1=2+1=3$

2. If $c(x)=sin(x)+2x$

Then

$y=c(x)$

$y=sin(x)+2x$

Using each of the values for x we have.

When x=0 the result is: $y=sin(0)+2(0)=0$

When x=0.008 the result is: $y=sin(0.008)+2(0.008)=0.000139+0.016=0.016139$

When x=0.027 the result is: $y=sin(0.027)+2(0.027)=0.000471+0.054=0.054471$

When x=0.064 the result is: $y=sin(0.064)+2(0.064)=0.001117+0.128=0.129117$

When x=0.125 the result is: $y=sin(0.125)+2(0.125)=0.002182+0.25=0.252182$

When x=0.216 the result is: $y=sin(0.216)+2(0.216)=0.003769+0.432=0.435769$

When x=0.343 the result is: $y=sin(0.343)+2(0.343)=0.005986+0.686=0.691986$

When x=0.512 the result is: $y=sin(0.512)+2(0.512)=0.008936+1.024=1.032936$

When x=0.729 the result is: $y=sin(0.729)+2(0.729)=0.012723+1.458=1.470723$

When x=1 the result is: $y=sin(1)+2(1)=0.017452+2=2.017452$

7 0

2 years ago

Insert parentheses on the left side of the equation to make the statement true for all values of p

lukranit [14]

7+5(p-p)=7
because 7+5p-5p=7
cross our the 5p because 5p-5p is 0
7=7
~JZ
Hope it helps!

3 0

3 years ago

{(1, 1), (2, 2), (3, 3), (4,4)} domain and range

jarptica [38.1K]

Answer:

Domain: 1, 2, 3, 4

Range: 1, 2, 3, 4

Step-by-step explanation:

The domain is the first coordinate in an ordered pair which is x. In this set of ordered pairs, the first coordinates ( x ) are 1, 2, 3, 4. The range is the second coordinate in an ordered pair which is y. The range of this set of ordered pairs is 1, 2, 3, 4.

Hope This Helps :)

6 0

2 years ago

Read 2 more answers