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uysha [10]
3 years ago
9

In which time period did Ancient Greek philosophers propose that all matter was composed of four fundamental substances: earth,

air, water, and wind? 8000 B.C. – 1000 B.C. 1000 B.C. – 450 B.C. 300 B.C. – 1400 A.D. 1774 – 1794 A.D. Time Period 1 Time Period 2 Time Period 3 Time Period 4 Time Period 1 Time Period 2 Time Period 3 Time Period 4
Chemistry
2 answers:
Andru [333]3 years ago
5 0

Answer:

  Time Period 2 1000 B.C. - 450 B.C.

Explanation:

  It was originated by the Greek philosopher Empedocles. He was a Greek pre-Socratic philosopher considered as the last one to have recorded his ideas in verse.

  He is known for originating the cosmogonic theory of the four classical elements. He called them the four "roots".

  I hope this answer helps you.

koban [17]3 years ago
3 0
<span>This theory was suggested around 450 BC</span>
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Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balance
ratelena [41]

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

Actual yield of Al = 30.25 g

Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

AlI₃(s) + 3K(s) → 3KI(s) + Al(s)

Molar mass of AlI₃ = 27 + (3×127)

= 27 + 381 = 408 g/mol

Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e

Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

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3 years ago
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Vladimir79 [104]
A mixture, because it contains multiple dyes and compounds

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Answer:

Atoms are often more stable when bonded to other atoms

Explanation:

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3 years ago
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zlopas [31]
CaSO4.2H2O is a white crystal at room temperature. It is soluble in water. Gypsum can be used as a fertilizer.


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Answer:

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