Answer:
V1 = 60 km/h
V2 = 40 Km/h
Step-by-step explanation:
The speed of an object is defined as
Speed = distance / time
Let
V1 be the speed of the faster car
V2 be the speed of the other car
t1 the time it took for the first car to arrive
t2 the time it took for the second car to arrive
d1 the distance traveled by first car
d2 the distance traveled by second car
We know thanks to the problem that
V1 = V2 + 20 Km/h
t1 = t2 - 1 hour
d1 = d2 = 120 Km
d1 = V1 * t1
d2 = V2* t2
V1 * t1 = V2* t2
V1* t1 = (V1 -20)*(t1 +1)
The system of equations
(V1 -20)*(t1 +1) = 120
V1 * t1 = 120
120 + (120/t1) -20*t1 = 140
(120/t1) -20*t1 = 20
Which gives,
t1 = 2
This means
V1 = 60 km/h
V2 = V1 - 20 Km/h = 40 Km/h
X ÷ 2 - 13 = 1
Write the division as a fraction

Multiple both sides of the equation by 2

Reduce the number with greatest common divisor 2

Multiply the numbers

Then u will have

Move constant to the right by adding its opposite sides

Eliminate the opposites

Then you have

Add the numbers
The answer is
Each roll has a 0.333 probability of being composite.
<em>(I just took the test,
B was the answer)</em>
Answer:
every 5 minutes ....
Step-by-step explanation: