Question

Given f(x) = x^2-3 and g(x)=x+2/x. Find (g°f)(4)

Answer 1

Answer:

$\[\frac{171}{13}\]$

Step-by-step explanation:

Given functions f(x) and g(x) are:

$f(x)=\[x^{2}-3\]$

$g(x)=\[x+\frac{2}{x}\]$

Then, (g o f)(x)=g(f(x))=g($\[x^{2}-3\]$)

$=\[x^{2}-3+\frac{2}{x^{2}-3}\]$

$=\[x^{2}-3+\frac{2}{x^{2}-3}\]$

Evaluating the value of (g o f)(x) when x=4,

$=\[4^{2}-3+\frac{2}{4^{2}-3}\]$

$=\[16-3+\frac{2}{16-3}\]$

$=\[13+\frac{2}{13}\]$

$=\[\frac{171}{13}\]$

Answer 2

Answer:

15/13

Step-by-step explanation: