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timurjin [86]
3 years ago
15

One fifth of the runs made in a cricket match

Mathematics
1 answer:
Gnesinka [82]3 years ago
4 0

Answer:

akjnajknlkicea

Step-by-step explanation:

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Over the summer, for every 11 okra seeds Dana planted, 6 grew into plants. If he planted 110 okra seeds, how many grew into plan
PilotLPTM [1.2K]

Answer:

A

Step-by-step explanation:

write it as a ratio

11:6 = 110: x

cross multiply

11x= 660

divide by 11 on both sides

x= 60

5 0
3 years ago
Kathy dropped a snowball from a building that is 39.2 meters tall. The equation t2 = 39.29.8 represents the amount of time, in s
DIA [1.3K]

Answer:

We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;

t² = 39.2 × 2/9.81

From which we have;

The time it takes the snowball to reach the ground is approximately 2.83 seconds

Step-by-step explanation:

The height of the building from which the ball is dropped, h = 39.2 m

The equation of the dropped a snowball, is given as follows;

t² = 39.2 × 9.8

Using the From the equation of free fall, we have;

s = u·t + 1/2·g·t²

Where;

u = The initial velocity = 0 m/s

t = The time of flight

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we get;

∴ s = The height from which the snowball is dropped = 39.2 m

Therefore, we get;

39.2 = 0×t + 1/2×9.81×t²

∴ t² = 39.2 × 2/9.81  ≈ 7.99

t = √(7.99) ≈ 2.83

The time it takes the snowball to reach the ground, t ≈ 2.83 s.

8 0
2 years ago
How can I solve this?!
Nutka1998 [239]

A

evaluate f(5) and f(2)

f(5) = 5m + b and f(2) = 2m + b, hence

f(5) - f(2) = 5m + b - 2m - b = 3m

the expression simplifies to

\frac{3m}{3} = 2 ( cross- multiply )

3m = 6 ( divide both sides by 3 )

m = 2 → A




8 0
3 years ago
Cho hệ các vector
shutvik [7]

Answer: whats the question?

Step-by-step explanation:

7 0
3 years ago
May I please receive help?<br> Please?
ANEK [815]

\huge\colorbox{red}T\colorbox{orange}h\colorbox{yellow}a\colorbox{green}n\colorbox{blue}k\colorbox{purple}s

6 0
2 years ago
Read 2 more answers
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