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Yakvenalex [24]
3 years ago
5

Which is bigger 5/8 or 0.58

Mathematics
1 answer:
Luden [163]3 years ago
7 0
Hello!

To compare the two, we must convert 5/8 to a decimal. We'll do that buy dividing the numerator by the denominator.

5 ÷ 8 = 0.625

Compare the two decimals.

0.625 vs. 0.580

So, 5/8 is obviously bigger than 0.58.
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X=2y-4<br>7x+5y=-66 <br> what is the x- value​
Gwar [14]

Answer:

x = -8

Step-by-step explanation:

x = 2y - 4 --- Equation 1

7x + 5y = -66 --- Equation 2

I will be using the substitution method to solve this.

Substitute x = 2y - 4 into Equation 2:

7x + 5y = -66

7(2y - 4) + 5y = -66

Evaluate.

14y - 28 + 5y = -66

Evaluate like terms.

19y - 28 = -66

Isolate 19y.

19y = -66 + 28

     = -38

Find y.

y = -38 ÷ 19

y = -2 --- Equation 3

Substitute y = -2 into Equation 1:

x = 2y - 4

x = 2(-2) - 4

Evaluate.

x = -4 - 4

x = -8

5 0
3 years ago
I need help finding this angle! I will mark you if you help!
Lady_Fox [76]

It's an acute angle because it's smaller than 90 degrees and isn't a straight line.

4 0
3 years ago
Read 2 more answers
NEED HELP PLEASE ASAP!!!!!!!!!!!!!!
DedPeter [7]

So you know that 30 + 30 + w + w = P. We also know the area is 240 square feet. Divide 240 by 30 to find the width of the area. 240 / 30 = 8. w = 8. So add 30 + 30 + 8 + 8 to find that P = 76. HOWEVER, remember that George is using part of his house as a wall instead of a fence. So subtract 8 from 76 to get 68 ft. George will need 68 ft. of fencing for his dog run.

4 0
3 years ago
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Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D
viva [34]

Answer:

\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C

Step-by-step explanation:

So we have the indefinite integral:

\int (\ln(x))^2dx

This is the same thing as:

=\int 1\cdot (\ln(x))^2dx

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}

Simplify:

du=\frac{2\ln(x)}{x}dx

And:

dv=(1)dx\\v=x

Therefore:

\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx

The x cancel:

=x\ln(x)^2-\int2\ln(x)dx

Move the 2 to the front:

=x\ln(x)^2-2\int\ln(x)dx

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

=x\ln(x)^2-2\int 1\cdot\ln(x)dx

Let u be ln(x) and let dv be (1)dx. Thus:

u=\ln(x)\\du=\frac{1}{x}dx

And:

dv=(1)dx\\v=x

So:

=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)

Simplify the integral:

=x\ln(x)^2-2(x\ln(x)-\int (1)dx)

Evaluate:

=x\ln(x)^2-2(x\ln(x)-x)

Now, we just have to simplify :)

Distribute the -2:

=x\ln(x)^2-2x\ln(x)+2x

And if preferred, we can factor out a x:

=x(\ln(x)^2-2\ln(x)+2)

And, of course, don't forget about the constant of integration!

=x(\ln(x)^2-2\ln(x)+2)+C

And we are done :)

8 0
3 years ago
Cone A has a radius of 12 inches and Cone B has a radius of 30 inches. If the cones are similar and the volume of Cone A is 48 f
Vika [28.1K]

Answer:

750 ft^3

Step-by-step explanation:

Given that the cones are similar, the first step would be to determine their linear scale factor; That is the ratio of their radii;

\frac{RadiusB}{RadiusA}=\frac{30}{12}=2.5

The next step is to determine the volume scale factors. Since the linear scale factor is 2.5, the volume scale factor would be;

volume scale factor = (linear scale factor)^3

                                 = 2.5^3 = 125/8

The volume of Cone B will thus be;

volume of Cone A * volume scale factor = 48 * 125/8 = 750 ft^3

6 0
3 years ago
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