Answer:
4) 0.001
Step-by-step explanation:
The amount (a) present in h hours is ...
a(h) = (initial value)×(1/2)^(h/(half-life))
6 days is 6×24 hours, so the amount remaining is ...
a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams
Answer:
4.24 to two decimal places
Answer:
<em><u>= </u></em><em><u>28.27m </u></em>
Step-by-step explanation:
<h3>
AREA OF CIRCLE <u>
= 2 π r</u></h3>
= 2 x 3.14 x 3m
<em><u>= 28.27m </u></em>
The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
Read more about exponential functions at:
brainly.com/question/11464095
#SPJ1
