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marissa [1.9K]
4 years ago
7

Can you find the distance between two points using absolute Value

Mathematics
1 answer:
Brut [27]4 years ago
7 0

Answer:

no can not find the distance between two point using absolute value

hope this help:)


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Simplify 200xyz3 .
sdas [7]

Simplify the Integer part of the SQRT

Step-by-step explanation:

Factor 200 into its prime factors

           200 = 23 • 52 

5 0
4 years ago
given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
ipn [44]

Answer:

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

Step-by-step explanation:

The weekly demand curve of a local wine producer is p= 50-0.1q

p = price

q = quantity

Revenue function R =Price \times Quantity

R=(50-0.1q)q

R=50q-0.1q^2

Cost function: c= 1500+ 10q

Profit function=R(x)-C(x)

Profit function= 50q-0.1q^2-1500-10q

Profit function= 40q-0.1q^2-1500   ----1

We have q = 500 - 10 p using p = 50 − 0.1q

P=-0.1 (500 - 10 p)^2 + 40 (500 - 10 p)- 1500\\P= -10 p^2 + 600 p - 6500

General quadratic equation:ax^2+bx+c=0

On comparing

a = -0.1 , b = 40 , c = -1500

Maximum Profit is at q = \frac{-b}{2a}=\frac{-40}{2(-0.1)}=200

To find price must a bottle of wine be sold to realise maximum profit

p= 50-0.1q

p= 50-0.1(200)=30

Substitute the value of q in profit function(1) get the maximum profit

So, Profit function= 40\left(200\right)-0.1\left(200\right)^{2}-1500=2500

Hence

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

8 0
3 years ago
VWX and NOP are similar. If mV = 44° and mP = 66°, what is<br> mW?
Sladkaya [172]

Answer: 70°

<u>Step-by-step explanation:</u>

ΔVWX ≅ ΔNOP     ⇒    ∠V=∠N, ∠W=∠O, and ∠X=∠P

Since ∠V=44° and ∠P=66°=∠X

then we can use the Triangle Sum Theorem:

∠V + ∠W + ∠X = 180°

44° + ∠W + 66° = 180°

        ∠W + 110° = 180°

        ∠W           = 70°

3 0
3 years ago
Find the missing number _____:7 = 12:21 <br><br> A. 3<br> B. 4<br> C. 14<br> D. 12
fgiga [73]
It would be 4:7 = 12:21
5 0
3 years ago
Read 2 more answers
An airplane flying into a headwind travels the 1800-mile flying distance between Pittsburgh, Pennsylvania and Phoenix, Arizona i
DaniilM [7]

If you put this info into a distance/rate/time table, you would have "against the wind" and "with the wind" as your 2 situations. If the distance from PA to AZ is 1800 miles, then the distance backwards, from AZ to PA is 1800 miles also. That number would go into the distance category for both situations. The rate is what we are looking for. The rate for "against the wind" is the speed of the plane minus the speed of the wind since the wind is blowing into the plane, slowing it down a bit. That looks like this: p - w where p is the speed of the plane and w is the speed of the wind. The rate for "with the wind" is p + w since the wind is pushing the plane along with it, making it fly faster. It took 3.6 hours to get from PA to AZ (you have to convert the 36 minutes into hours) and it took 3 hours to go from AZ to PA. In table form that looks like this:

distance = rate x time

against wind 1800 = p - w x 3.6

with wind 1800 = p + w x 3

Since distance = rate times time, then the first equation going along in the first row is 1800 = 3.6(p - w) and

1800 = 3.6p - 3.6w

Going along in the second row we have 1800 = 3p + 3w. Let's solve this equation for p: 1800 - 3w = 3p and dividing everything by 3 we have

600 - w = p. Now we have a viable substitution to make into the first equation we wrote. If p = 600 - w, then 1800 = 3.6(600 - w) - 3.6w

and 1800 = 2160 - 3.6w - 3.6w. Combining like terms we have

-360 = -7.2w and solving for w we have that w = 50. That means that the speed of the wind is 50 mph. Now we can sub that value in for w to solve for p. 600 - w = p so 600 - 50 = p. That means that p = 550mph. The wind blows at a rate of 50 mph while the plane travels at a rate of 550 mph. There you go!


5 0
4 years ago
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