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Taya2010 [7]
3 years ago
6

A spinner is divided into five congruent sections, numbered 1 through 5. If the arrow on the spinner is spun, what is the probab

ility that the arrow on the spinner will NOT land on a section labeled with an odd number on the first try?
A. 3/5
B.2/3
C.1/2
D.2/5
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
6 0
D.2/5 because 3/5 are odd so the remaining 2 are even so 2/5 are not odd!
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5231+4331=9562 3696+6939
7nadin3 [17]

Answer:

10635

Step-by-step explanation:

Honestly, I dunno. I just added it.

5 0
3 years ago
Read 2 more answers
The mean of the data set is 15.What number is missing? 9,12,16,18,23
maxonik [38]

The number 12 is missing in the data set.

<u>Step-by-step explanation</u>:

  • The numbers are 9,12,16,18,23.
  • The missing number is assumed to be 'x'

Mean = Sum of the integers / Total number of integers.

15 = (9+12+16+18+23+x) / 6

15 = (78+x) / 6

90 = 78+x

x = 90-78

x = 12

3 0
3 years ago
What is x. Please show *all* the steps.
Zolol [24]

The equation 5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0 is a quadratic equation

The value of x is 8 or 1

<h3>How to determine the value of x?</h3>

The equation is given as:

5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0

Rewrite as:

-5/x - 2 + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0

Take the  LCM

[-5(x + 2) + (x -5)(x- 2)]\[x^2 - 4 + [3x + 8]/[x^2 - 4] = 0

Expand

[-5x - 10 + x^2 - 7x + 10]/[x^2 - 4] + [3x + 8]/[x^2 - 4] = 0

Evaluate the like terms

[x^2 - 12x]/[x^2 - 4] + [3x + 8]/[x^2 - 4 = 0

Multiply through by x^2 - 4

x^2 - 12x+ 3x + 8 = 0

Evaluate the like terms

x^2 -9x + 8 = 0

Expand

x^2 -x - 8x + 8 = 0

Factorize

x(x -1) - 8(x - 1) = 0

Factor out x - 1

(x -8)(x - 1) = 0

Solve for x

x = 8 or x = 1

Hence, the value of x is 8 or 1

Read more about equations at:

brainly.com/question/2972832

8 0
2 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title="
Ira Lisetskai [31]
1/3
Reduces los números usando el máximo común divisor= 2
6 0
3 years ago
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