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4vir4ik [10]
4 years ago
7

How do you solve 7a+10=2a

Mathematics
2 answers:
amm18124 years ago
4 0
7a+10=2a -7a. -7a 10=-5a Divide by -5 and u get ur answer
sammy [17]4 years ago
3 0
Subtract 7a from both sides giving you 10=-5a and divide everything by 5. This gives you a=-2
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Anna gets paid $8.75/hour working as a barista at Coffee Break. Her boss pays her $9.00/hour for creating the weekly advertiseme
vladimir1956 [14]

Answer:

i believe it would be $443.75

Step-by-step explanation:

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8.75+9.00= 17.75 x 25= 443.75

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7 0
4 years ago
What are the first 50 decimal numbers in pie 3.14159265 Then what?
tester [92]

Answer:

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7 0
3 years ago
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According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 9x4 – 2x2 – 3x + 4?
Tanzania [10]
The coefficients of x4 is 9. It has factors of 1, 3, and 9. The constant is 4. It has factors of 1, 2, and 4.
The (positive and negative) ratios of the factors of the coefficient of the x4 and the constant 4 are the potential rational roots of the function.
The answers are:
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5 0
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Is this right? if it isn't, what IS right?
tangare [24]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

3 0
3 years ago
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