As 1 inch = 2.54 cm.
As Annalisa is 64 inches tall,
so the height of Annalisa in centimeter = 64 x 2.54 cm = 162.5 cm (approximately).
Stefen is about 7.5 centimeters taller than Annalisa,
So, height of Stefen in centimeter= 162.5+7.5=170 cm.
and the height of Stefen in inches = 170/ 2.54 cm= 67 inches (approximately).
Keiko is about 1.5 inches shorter than Stefen,
So, the height of Keiko in inches= 67-1.5=65.5 inches.
and the height of Keiko in centimeter = 71.5 x 2.54 cm= 166.5 cm (approximately).
Hence, Annalisa is 64 inches or about 162.5 cm tall.
Stefan is about 67 inches or about 170 cm tall.
Keiko is about 65.5 inches or about 166.5 cm tall.
First, the graph is a parbole, this is a square function, so it can not be the option a) because it is a linear function.
Second, the vertix of the parabole is the point (0,3), so use the general vertex form of the parabole:
y = A(x - h)^2 + k, where h and k represent the vertex (h,k).
So, the form of the funtion is y = A (x-0)^2 - 3 = Ax^2 - 3
Now, you also know that the roots of the parabole are close to -1 and 1 but they are not those exact value.
So, find the roots for any of the possible options:
b) f(x) = 2x^2 - 3 = 0 => 2x^2 = 3 => x^2 = 3/2 => x = +/- √(3/2) ≈ +/- 1.22
That is a very plausible answer
c) f(x) = (1/2)x^2 - 3 = 0 => x^2 = 2*3 = 6 => x = +/- √6 ≈ +/- 2.45, which is very far from the roots shown on the graph.
3) f(x) = x^2 - 3 = 0 => x^2 = 3 => x = +/- √3 ≈ +/- 1.73, which is not so close to +/- 1.
So, the answer is the option b) f(x) = 2x^2 - 3
Answer:
the length of RS to the nearest tenth of a foot is 240.6ft
Answer:
median = 5
Step-by-step explanation:
1,2,4,6,7,9
median = middle position = (4+6)/2 = 5
It doesn’t really matter which variable you isolate first but usually you would use the one that’s by itself already. like for example one of the equations was y = 8. you would already have your y solve for so you would just have to plug that in for y in the other equation. personally, i usually do x first unless one of the equations has either x or y by itself already. i think its easier to just do x first and then solve for y after that, but it just depends on what the equations are; sometimes it might be easier to just do y first. hope this helps!
