Question

In the xy coordinate plane the slope of line p 1/2 and it’s x-intercept is -3. Find the equation of a line that is perpendicular to p and intersects p at is x-intercept
A) y=-2x-3

B) y=-2x+3

C) y=-2x-6

D) y= 2x+6

Answer 1

Answer:y=-2x+6

Step-by-step explanation:

Let $m_{1}$ be the slope of the given line and $m_{2}$ be the slope of the new line.

given,$m_{1}=\frac{1}{2}$.

Since,the given line and the new line are perpendicular,

$m_{1}m_{2}=-1$

So,$m_{2}=-2$

It is given that the new line passes through x-intercept of the given line.

The x-intercept of the given line is $(-3,0)$

The equation of the line passing through $(x_{1},y_{1})$ and slope $m$ is $y-y_{1}=m(x-x_{1})$

So,the line is $y-0=-2(x+3)$

$y=-2x-6$