Question

Please help! It's Algebra.

Answer 1

Answer:

Square: x= +or - $\sqrt{7}$, Triangle: x= + or - $\sqrt{23}$

Step-by-step explanation:

For the square

4$x^{2}$=28

dvide by four:

$x^{2}$=7

Take the square root of both sides

x= +or - $\sqrt{7}$

For the Triangle

(1/2) (2x) (2x)=46

2$x^{2}$=46

Divide by 2

$x^{2}$=23

x= + or - $\sqrt{23}$