All categories

3 years ago

If a car wheel has a 14 inch radius through what angle does the wheel turn when the car rolls forward 5ft?

Mathematics

1 answer:

Artist 52 [7]3 years ago

8 0

Answer:

Angle will be 4.285 radian in degree it will be equal to $245.677^{\circ}$

Step-by-step explanation:

We have given radius of the car wheel r = 14 inch

And car rolls forward by 5 feet

So arc = 5 feet

We know that 1 feet = 12 inches

So 5 feet = 5×12 = 60 inches

Arc is equal to $arc=radius \times angle$

So $60=14\times \Theta$

$\Theta =4.285radian$

$=4.285\times \frac{180}{\pi }=245.677^{\circ}$

You might be interested in

In circle D, ∠EDH ≅ ∠EDG

tangare [24]

Answer:

what's the question, is it what's the ,ensure mentioned or something.

6 0

3 years ago

Can someone help me please?

IgorLugansk [536]

Answer:

uh i dont know lol im new how do i use this thing bahahaha

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which sample fairly represents the population? Select two options.

ExtremeBDS [4]

Answer:

b) observing every person walking down Main Street at 5 p.m. one evening to determine the percentage of people who wear glasses.

d) taking a poll in the lunch room (where all students currently have to eat lunch) to determine the number of students who want to be able to leave campus during lunch.

Step-by-step explanation:

These are the two options that are most likely to give you a sample that fairly represents the population. In the first case, the sample that you obtain is likely to be a good representation because Main Street is a road where a great variety of people walk. Moreover, 5 pm is also a time that will allow you to see a great number of different people. The second answer will also give you a good sample, as the poll would include all students in the lunch room, which is all students in the school (the whole population).

7 0

4 years ago

Read 2 more answers

Solve each equation by factoring.

nevsk [136]

Answer:

k=1/3; k=-2/5

Step-by-step explanation:

$15k^2+k-4=-2\\15k^2+k-2=0\\(3k-1)(5k+2)=0\\3k-1=0; 5k+2=0\\k=1/3; k=-2/5$

4 0

3 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

6 0

3 years ago