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ZanzabumX [31]
3 years ago
10

What is the solution for -3(6x+5)-2(1-17x)=3(5+5x)

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0

-3(6x+5)-2(1-17x)=3(5+5x)

Mutiply the first bracket by -3

(-3)(6x)= -18x

(-3)(5)= -15

Mutiply the second bracket by -2

(-2)(1)= -2

(-2)(-17x)= 34x

Mutiply the third bracket by 3

(3)(5)= 15

(3)(5x)= 15x

-18x-15-2+34x= 15+15x

-18x+34x-15-2= 15+15x

16x-17= 15+15x

move 15 to the other side

sign changes from +15 to -15

16x-17-15= 15-15+15x

16x-32= 15x

move -32 to the other side

sign changes from -32 to +32

16x-32+32=15x+32

16x= 15x+32

move 15x to the other side

sign changes from +15x to -15x

16x-15x=15x-15x+32

x= 32

Answer: x= 32

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The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

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<h3>Which trigonometric functions are positive in which quadrant?</h3>
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(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

y= 3\cos(2(x + \pi/2)) - 2

The options are:

  1. y= 3\sin(2(x + \pi/4)) - 2
  2. y= -3\sin(2(x + \pi/4)) - 2
  3. y= 3\cos(2(x + \pi/4)) - 2
  4. y= -3\cos(2(x + \pi/2)) - 2

Checking all the options one by one:

  • Option 1: y= 3\sin(2(x + \pi/4)) - 2

y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

  • Option 2: y= -3\sin(2(x + \pi/4)) - 2

This option if would be true, then from option 1 and this option, we'd get:
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which isn't true for all values of x.

Thus, this option is not same as the given function.

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The given function is y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

This option's function simplifies as:

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Thus, this option isn't true since \sin(2x) \neq \cos(2x) always (they are equal for some values of x but not for all).

  • Option 4: y= -3\cos(2(x + \pi/2)) - 2

The given function simplifies to:y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

The given option simplifies to:

y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2

Thus, this function is not same as the given function.

Thus, the function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

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